4 Designing the Power Supply System
Item
Power supply
cable length
Voltage at
power supply
terminal of ex-
ternal power
supply
According to the table of voltage drop in the internal circuits of IO-Link Master Units and power sup-
ply cables, the voltage drop for each Unit from each power supply is determined as follows.
Voltage drop in
Unit
internal circuits
name
ILM1
---
ILM2
Voltage drop in
internal circuits
of ILM1: 0.36 V
•
ILM3
Voltage drop
in internal cir-
cuits of ILM1:
0.36 V
•
Voltage drop
in internal cir-
cuits of ILM2:
0.18 V
4-18
The cable length is as follows.
ILM1
Power supply
cable 1: 1 m
Unit/input power supply
Output power supply
•
Unit/input power supply: 24.0 VDC
•
Output power supply: 24.0 VDC
Voltage drop in power
supply cables
of Unit
•
Voltage drop in pow-
er supply cable 1:
0.80 V
•
Voltage drop in pow-
er supply cable 1:
0.80 V
•
Voltage drop in pow-
er supply cable 2:
0.60 V
•
Voltage drop in pow-
er supply cable 1:
0.80 V
•
Voltage drop in pow-
er supply cable 2:
0.60 V
•
Voltage drop in pow-
er supply cable 3:
0.30 V
Conditions
ILM2
ILM3
Power supply cable 3: 1 m
Power supply cable 2: 1 m
Use the voltage drop at 8 A because the sum of the
current consumption of each Unit from external power
supplies is 7.76 A.
For the voltage drop in power supply cable 1, use the
value of ILM1.
For the voltage drop in power supply cable 2 and in-
ternal circuits of ILM1, use the current value calculat-
ed as follows.
(Sum of current consumption of each Unit from exter-
nal power supplies) - (Sum of total current consump-
tion of ILM1) = 7.76 A - 3.30 A = 4.46 A
Therefore, use the value at 6 A.
For the voltage drop in power supply cable 1 and
power supply cable 2, and voltage drop in the internal
circuits of ILM1, use the values of ILM1 and ILM2.
For the voltage drop in power supply cable 3 and in-
ternal circuits of ILM2, use the current value calculat-
ed as follows.
(Sum of current consumption of each Unit from exter-
nal power supplies) - (Sum of total current consump-
tion of ILM1 and ILM2) = 7.76 A - 3.30 A - 2.23 A =
2.23 A
Therefore, use the value at 3 A.
NXR-series IO-Link Master Unit for EtherCAT User's Manual (W640)
Remarks