GE MAC 5500 Service Manual page 36

Resting ecg analysis system
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2-18
Equipment Overview: Theory of Operation
access both the static (5 bits) and dynamic (3 bits) portions of a pixel separately, and
simultaneously. The SDRAM bus is effectively split into a "dynamic byte lane" and
a "static byte lane". The resulting improvement in drawing algorithm speed is
substantial.
The 16-bit wide bus of the SDRAM allows each read/write cycle to access two bytes
of data. During writes, upper and lower byte strobes allow independent writing of
either or both bytes. During reads, both bytes are always presented. Unneeded read
data bits are ignored by the CPU. The LCD controller takes advantage of the
individual accessibility of the bytes to eliminate the need for the CPU to pack and
unpack the static and dynamic pixels. At the expense of unused memory bits (a
small expense as less than 1/16th of the entire SDRAM space is needed at all) the
LCD controller maps the 5 bits of each static pixel into one SDRAM byte lane (the
static lane), and the 3 bits of each static pixel into the other (the dynamic lane).
Unused bits in each lane are written as zeroes, and ignored on reading.
On the CPU side, the SDRAM frame buffer appears as two regions, the static and
dynamic planes. Each plane is a contiguous array of 480 lines of 640 pixels each.
Within the static plane, the lower 3 bits (the dynamic bits) of each pixel byte are
ignored on writes, and read as zeroes. Within the dynamic plane, the upper 5 bits of
each pixel byte (the static bits) are ignored on writes and read as zeroes. The
dynamic plane is located 1/2 Mbyte above the static plane and address bit A19 is
used to differentiate between them. The interface from the LCD controller to the
CPU is 16-bits wide, allowing two pixel bytes to be moved in each read/write cycle.
In the 16-bit wide SDRAM, each word (independently byte addressable) contains
both a static and a dynamic pixel byte, each in their own lanes. When the CPU
writes a pixel to the static plane, the upper five bits of the byte are routed to the static
byte lane (the lower three bits are set to zero) and the dynamic byte lane is disabled.
When the CPU reads a static pixel, both the static and dynamic byte lanes are
accessed, but only the upper five bits of the static byte lane are passed on to the CPU
(the lower three bits are zeroed). Access to the dynamic plane proceed in much the
same manner, with the appropriate bits being routed to the dynamic byte lane while
the static byte lane is disabled.
Because each 16-bit word of SDRAM contains one pixel, and each 16-bit access of
the CPU into the frame buffer contains two, the LCD controller must pack/unpack
pixels on the fly. During writes, if the CPU signals a single byte write, the LCD
controller writes the byte onto the proper lane (as determined by A19) of one
memory word. If the CPU signals a two byte write, the LCD controller queues a two
cycle burst write into two consecutive words of SDRAM. On reads, the LCD
controller always reads two pixels from memory and packs them into a single word
for access by the CPU, which may use both pixels, or ignore one.
By design, SDRAMs are faster when data can be moved in sequential bursts. The
Atmel ARM CPU asynchronous bus interface does not support burst accesses, so the
opportunity to burst is limited. The LCD controller does take advantage of the 16-bit
wide nature of the asynchronous bus to allow bursts of two pixels into and out of
memory when possible. This nearly doubles frame buffer bandwidth over a
byte-at-a-time interface. Finally, as mentioned previously, the CPU is able to
manipulate individual pixels in either plane without resorting to read-modify-write
access cycles. This provides another twofold improvement in memory bandwidth.
Line Buffer – Within each line of LCD video data, bytes must move from the frame
buffer to the scroller/CLUT in an unbroken stream at 48Mhz. Although the frame
buffer is capable of burst transfers of 60Mpixels/sec, it cannot be depended on to
MAC 5500 resting ECG analysis system
2020299-020
Revision E

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