Wiring; Wiring Procedure - Mitsubishi Electric FX5 User Manual
Melsec iq-f series
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- Programming manual (1112 pages) ,
- User manual (558 pages) ,
- Reference manual (44 pages)
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■Calculation example 3
Calculation of required time when Pr. 10 to Pr. 14 [(s2) = 5] are written by the IVBWR instruction
Tinv=T
+T
+T
=851[ms]
1
2
3
T
=10(s2)=50[ms], T
=1[ms]
1
3
Calculate "T
" as follows because Pr.10 to Pr. 14 do not require change of the 2nd parameter and the time required for writing
2
is same in each parameter.
T
= ( 2 × (T
+T
) + T
[1]+T
2
4
5
6
Time required to write Pr. 10
= 5 × ( 2 × (T
+T
) + T
[1] + T
4
5
6
(s2)
1
T
= ( INT (
+1 ) × 10 ) + ( INT (
4
10
1
T
= INT (
+1 ) × 10 = 10 [ms]
5
10
T
[1]+T
[1]+T
7
8
T
[1] = ( INT (
6
10
T
[1] + T
[1] + T
[1] = 7.8 + 12 = 19.8 [ms]
7
8
9
T
[1] + T
[1] = ( (
7
9
19200
T
[1] = 12 [ms]
8
T
[2]+T
[2]+T
7
8
T
[2] = ( INT (
6
10
T
[2] + T
[2] + T
[2] = 8.9 + 30 = 38.9 [ms]
7
8
9
T
[2] + T
[2] = ( (
7
9
19200
T
[2] = 30 [ms]
8
Tinv = T
+ T
+ T
= 50 + 800 + 1 = 851 [ms]
1
2
3
4.5
Wiring
This section explains about the wiring.
Wiring procedure
1.
Select the connection method
Confirm the inverter connection method. (Page 78 Connection method)
2.
Make arrangements for wiring
Prepare cables (Page 80 Cable), distributors (Page 82 Connection devices (RJ45 connector and distributor))
and termination resistors (Page 83 Termination resistor setting) required for wiring.
3.
Turn OFF the PLC power
Before wiring, make sure that the PLC power is OFF.
4.
Wire the communication equipment.
Connect RS-485 communication equipment of PLC with the communication port of the inverter. (Page 84
Connection diagram)
5.
Set or connect termination resistors.
Set or connect termination resistor of the inverter farthest from the PLC. (Page 83 Termination resistor setting)
6.
Connect (Ground) a shielding wire (Class-D grounding)
When using a twisted pair cable, connect a shielding wire. (Page 84 Shielded wiring)
[2] ) + ( 2 × (T
+T
) + T
[3]+T
6
4
5
6
Time required to write Pr. 11
[2] ) = 5 × ( 2 × (30+10) + 30 + 50 ) = 800 [ms]
6
11
+1 ) × 10 ) = 30 [ms]
10
[1]
1
9
) +1 ) × 10 + ( INT (
10
1
) × (11+4) × 10 ) × 1000 = 7.8 [ms]
[2]
1
9
) +1 ) × 10 + ( INT (
10
1
) × (13+4) × 10 ) × 1000 = 8.9 [ms]
[4] ) + •••
6
19.8
+1 ) × 10 ) = ( INT (
+1 ) ×10 +10 = 30 [ms]
10
38.9
+1 ) × 10 ) = ( INT (
+1 ) ×10 +10 = 50 [ms]
10
4 INVERTER COMMUNICATION
4.5 Wiring
4
77
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