Daikin VRV Plus Series General Information Manual page 103

R-407c
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Si33-003.book Page 99 Monday, June 25, 2001 9:06 AM
SiE33-003
Calculating
Refrigerant Charge
+
+
+
Full Refrigerant
The amount of refrigerant needed to completely recharge the system equals to that of the refrigerant
Recharging
charge at factory set (marked on name plate) plus the above additional charge.
Extracting
Open the stop valves on both the gas line and liquid line, and extract the refrigerant from the service ports.
Refrigerant
General Information
Calculate the charge of refrigerant needed as described below, and add accordingly.
Record your calculations for use by aftercare service.
Total length of liquid line piping (φ 22.2)
Total length of liquid line piping (φ 5.9)
Total length of liquid line piping (φ 9.5)
0 :RSXYP16,18,24,28
0.4:RSXYP30
0.6:RSXYP26
0.8:RSXYP20
Example of refrigerant branch using REFNET joint for RSXYP28
Outdoor unit
REFNET joint (A-G)
H3
Q
g
a
b
c
d
e
f
A
B
C
D
E
F
G
p
h
i
j
k
l
m
n
H2
1
2
3
4
5
6
7
8
Indoor units (1-8)
(V1057)
Example of refrigerant branch using REFNET joint and REFNET header for RSXYP28
Outdoor unit
REFNET joint (A-B)
H3
Q
i
a
A
B
b
j
H1
Refnet header
7
c
d
e
f
g
h
1
2
3
4
5
6
Indoor units (1-8)
(V1058)
Example of refrigerant branch using REFNET header for RSXYP28
Outdoor unit
REFNET header
H3
Q
a
i
b
c
d
e
f
g
h
H2
1
2
3
4
5
6
7
8
Indoor units (1-8)
(V1059)
Total length of liquid line piping (φ 19.1)
+
Total length of liquid line piping (φ 12.7)
+
Total length of liquid line piping (φ 6.4)
+
a : φ 22.2 × 10m
b : φ 22.2 × 2m
c : φ 22.2 × 5m
d : φ 19.5 × 5m
e : φ 15.9 × 5m
H1
f : φ 12.7 × 5m
g : φ 9.5 × 5m
h : φ 9.5 × 5m
R = 17 × 0.39 + 5 × 0.28 + 5 × 0.19 + 5 × 0.12
a+b+c
d
+ 15 × 0.06 + 30 × 0.023 + 0
g+h+l
i+j+k+m+n+p
= 6. 63 + 1.4 + 0.95 + 0.6 + 0.9 + 0.69 + 0 = 11.17kg
a : φ 22.2 × 30m
b : φ 15.9 × 10m
c : φ 9.5 × 10m
d : φ 9.5 × 10m
e : φ 9.5 × 10m
k
8
f : φ 9.5 × 10m
H2
R = 30 × 0.39 + 10 × 0.19 + 10 × 0.12
a
b
+ 40 × 0.06 + 49 × 0.023 + 0 = 18.32
c+d+e+f
g+h+j+k
a : φ 22.2 × 20m
b : φ 9.5 × 10m
c : φ 9.5 × 10m
d : φ 6.4 × 20m
e : φ 6.4 × 10m
H1
R = 20 × 0.39 + 20 × 0.06 + 123×0.023
a
b+c
= 7.8 + 1.2 + 2.83 = 11.83
11.8kg
: http://splitoff.ru/tehn-doc.html
Appendix
(V1144)
i : φ 6.4 × 5m
j : φ 6.4 × 5m
k : φ 6.4 × 5m
l : φ 9.5 × 5m
m : φ 6.4 × 5m
n : φ 6.4 × 5m
p : φ 6.4 × 5m
e
f
ò
11.2kg
(V1145)
g : φ 6.4 × 10m
h : φ 6.4 × 20m
i : φ 12.7 × 10m
j : φ 6.4 × 10m
k : φ 6.4 × 9m
i
ò
18.3kg
(V1157)
f : φ 6.4 × 23m
g : φ 6.4 × 20m
h : φ 6.4 × 20m
i : φ 6.4 × 30m
d+e+f+g+h+i
ò
(V1146)
99

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