Toshiba GR200 Series Instruction Manual page 411

Line differential protection ied
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determined with Equations (2.32-18) to (2.32-23):
where,
Va: Fault voltage (Va=Va0)
Iα:
Fault current (=(2Ia−Ib−Ic)/3)
Iα':
Current change before and after the fault (=(2Ia−Ib−Ic)/3−(2ILa−ILb−ILc)/3)
Iα":
Complex conjugate of Iα'
Ia, Ib, Ic:
Fault currents in phase-a, phase-b, and phase-c
ILa, ILb, ILc:
I0s:
Current in zero-sequence at local terminal
I0m:
Adjacent-line current in zero-sequence in parallel lines
R1:
Resistance component of line impedance1 in positive-sequence
Χ1:
Reactance component of line impedance1 in positive-sequence
R0:
Resistance component of line impedance2 in zero-sequence
Χ0:
Reactance component of line impedance2 in zero-sequence
R0m:
Mutual resistance3 between parallel lines in zero-sequence
X0m:
Mutual reactance3 between parallel lines in zero-sequence
Ka:
Compensation factor4 for imbalance impedance
Im( ):
Expression of imaginary part when a value is placed in parentheses
Re( ):
Expression of real part when a value is placed in parentheses
L:
Line length5 in the kilometer or mile
• :
Symbol of Vector product
Note: For example, user should set the R 1 and the X 1 with settings [FL_1R1] and
1
setting [FL_1X1] respectively, when the impedance of line GJ is considered in
2��
− ��
��
��
=
α
2��
− ��
– ��
��
��
��
��
' =
α
3
・��
�� = ��
��
�� = ��
∙ ��
∙ ��
" + ��
∙ ��
1
α
α
0
0s
�� = X
∙ ��
∙ ��
" + X
∙ ��
1
α
α
0
0s
Im ( �� ) × L
χ =
{ Im ( �� ) + Re(��) } × ��
Load-current in phase-a, phase-b, and phase-c before the fault
- 388 -
– ��
��
��
3
2��
− ��
– ��
����
����
����
3
"
α
∙ ��
"+��
∙ ��
∙ ��
"
α
0��
0m
α
∙ ��
"+X
∙ ��
∙ ��
"
α
0��
0m
α
��
6F2S1914 (0.49)
(2.32-18)
(2.32-19)
(2.32-20)
(2.32-21)
(2.32-22)
(2.32-23)
GRL200 (Soft 033 & 037)

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