ABB RELION 670 Series Applications Manual page 429

Transformer protection
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1MRK 504 152-UEN B
The fault current, in the fault point, can be calculated as:
=
I
3I
j
0
EQUATION1944 V1 EN-US
The impedance Z
point apparatus) the impedance is equal to the capacitive coupling between the phase
conductors and earth:
= -
Z
jX
0
EQUATION1945 V1 EN-US
Where
I
j
X
c
In a system with a neutral point resistor (resistance earthed system) the impedance Z
calculated as:
-
=
Z
0
-
jX
EQUATION1946 V1 EN-US
Where
R
n
In many systems there is also a neutral point reactor (Petersen coil) connected to one or more
transformer neutral points. In such a system the impedance Z
= -
Z
jX // 3R // j3X
0
EQUATION1947 V1 EN-US
Where
X
n
Now consider a system with an earthing via a resistor giving higher earth fault current than the
high impedance earthing. The series impedances in the system can no longer be neglected.
The system with a single phase to earth fault can be described as in Figure 261.
Application manual
×
3 U
=
phase
+ ×
Z
3 R
0
f
is dependent on the system earthing. In an isolated system (without neutral
0
×
3 U
= -
phase
j
c
I
j
is the capacitive earth fault current at a non-resistive phase-to-earth fault
is the capacitive reactance to earth
×
jX 3R
c
n
+
3R
c
n
is the resistance of the neutral point resistor
=
c
n
n
3X X
n
is the reactance of the Petersen coil. If the Petersen coil is well tuned we have 3X
impedance Z
will be: Z
= 3R
0
0
9R X X
n
n
c
(
)
+
×
-
j3R
3X
X
c
n
n
c
n
Current protection
(Equation 446)
(Equation 447)
(Equation 448)
can be calculated as:
0
(Equation 449)
= X
In this case the
n
c
Section 8
can be
0
423

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