Tool Lengths L1, L2, L3 Assignment: Lentoax - Siemens SINUMERIK 840D sl Function Manual

N40
N50
N60
N70
N80
N90
_CORCOMP is 0, therefore, the coordinate value of the geometry component acting in the Z
direction must be replaced by the offset value 0.333. The resulting total tool length is thus L1
= 0.333 + 1.000 = 1.333
Example 2
N10
N20
N30
N40
N50
N60
N70
N80
N90
_CORCOMP is 1, therefore, an offset value of 0.333 acting in the Z direction is added to the
wear value of 1.0.
Therefore, the resulting total tool length is L1 = 10.0 + 1.333 = 11.333.
18.13

Tool lengths L1, L2, L3 assignment: LENTOAX

LENTOAX function
The "LENTOAX" function provides information about the assignment of tool lengths L1, L2
and L3 of the active tool to the abscissa, ordinate and applicate. The assignment of abscissa,
ordinate and applicate to the geometry axes is affected by frames and the active plane (G17
- G19).
Only the geometry component of a tool ($TC_DP3[x,y] to $TC_DP5[x,y]) is considered, i.e. a
different axis assignment for other components (e.g. wear) has no effect on the result.
The "LENTOAX" function is a predefined subprogram. It must, therefore, be programmed in a
separate block.
Syntax:
Status = LENTOAX(_AXIND, _MATRIX, _COORD)
Basic Functions
Function Manual, 01/2015, 6FC5397-0BP40-5BA2
$TC_DP12[1,1]=
_CORVAL[0] =
t1 d1 g17 g0
r1 = settcor(_CORVAL, "G", 0, 0, 2)
t1 d1 x0 y0 z0
M30
def real _CORVAL[3]
$TC_DP1[1,1] =
$TC_DP3[1.1] =
$TC_DP12[1,1]=
_CORVAL[0] =
t1 d1 g17 g0
r1 = settcor(_CORVAL, "W", 0, 1, 2)
t1 d1 x0 y0 z0
M30
18.13 Tool lengths L1, L2, L3 assignment: LENTOAX
1.0 ; Wear L1
0.333
; ==>
120 ; Milling tool
10.0 ; Geometry L1
1.0 ; Wear L1
0.333
; ==>
W1: Tool offset
MCS position X0.000 Y0.000
Z1.333
MCS position X0.000 Y0.000
Z11.333
1531