Casio CLASSPAD 330 3.04 User Manual page 138

Problem
Divide 21 by 6 and 7, and
determine the remainder
of both operations.
(iMod(21, {6, 7})
Permutation (nPr) and Combination ( n C r )
Total Number of Permutation
n ! n !
nPr = ––––– nPr = –––––
( n – r )! ( n – r )!
Total Number of Combination
n ! n !
nCr = ––––––– nCr = –––––––
r ! ( n – r )! r ! ( n – r )!
Problem
How many different
permutations are possible
when you have 10 different
objects and arrange them
four at a time?
P = 5040
10 4
How many different
combinations are possible
when you have 10 different
objects and remove four at
a time?
C = 210
10 4
2-4-11
Function Calculations
U e thi keyboard:
mth abc cat
Func
U e thi keyboard:
mth abc cat
CALC Func
CALC Func
20090601
Operation
2D
[iMod] 21
Operation
2D
10 4
10 4
6 7