Casio CLASSPAD 330 3.04 User Manual page 209

normPDf({1, 2},{1, 2}, 0) = {0.24, 0.12}
normPDf({1, 2},{1, 2},{1, 0}) = {0.40, 0.12}
The following explains how to specify list data in arguments and how calculation results are
output.
(a) Specifying list data for a single argument
• Basically, you can specify any list you like, but the each of the elements in the list must
be in accordance with the conditions required by the argument of the function being
used.
• Calculation is performed on each element within the list and results are output as
shown below.
x σ σ
normPDf( , { ,
1
x σ
= {<normPDf( ,
(b) Specifying list data for multiple arguments
• In this case, all of the lists must have the same number of elements. Otherwise an
Invalid Dimension error will occur.
• Calculation is performed on each element within the list and results are output as
shown below.
x x
normPDf({ , }, {
1 2
x σ
= {<normPDf( ,
1
A ignment of Li t Data Calculation Re ult to Variable
Using the list data in the argument of the Distribution function causes calculation results to
be output as list data, which is assigned as-is to the "ans" variable.
In addition to the "ans" variable, calculations that use the Distribution function causes
calculation results also to be assigned to certain system variables. For example, the normal
probability density variable returned by normPDf is assigned to system variable
the last element of the list data will be assigned to a system variable as a calculation result.
For information about which calculation result is assigned to which variable, see the
"Calculation Result Output" item for each command in "7-11 Distributions" (pages 7-11-3 to
7-11-25).
normPDf
Function: Returns the normal probability density for a specified value.
x
Syntax: normPDf( [, , )]
• When and are skipped,
Example: To determine the normal probability density when
Menu Item: [Action][Distribution][normPDf]
For more information, see "Normal Probability Density" on page 7-11-3.
2-8-49
Using the Action Menu
μ
}, )
2
μ
, ) calculation result>, <normPDf(
1
σ σ μ
, }, )
1 2
μ
, ) calculation results>, <normPDf(
1
= 1 and = 0 are used.
20090601
x σ μ
, , ) calculation result>}
2
x σ μ
, , ) calculation results>}
2 2
prob
x
= 37.5, = 2,
. Only
= 35