Dimensioning Climate Control Equipment - Siemens SINAMICS S120 Equipment Manual

8.7.4

Dimensioning climate control equipment

Cabinet manufacturers provide calculation programs for selecting climate control equipment.
It is always necessary to know the power loss of the components and equipment installed in
the cabinet.
The physical relationship is shown in the following example.
Figure 8-22
q = thermal power that has to be dissipated through a cooling unit [W / K]
Q = power loss [W]
∆T = temperature difference between the room and cabinet interior [K]
k = thermal resistance value, e.g. sheet-steel, painted 5.5 [W / (m
A = free-standing cabinet surface area [m
Table 8-25 Example, calculating the power loss of a drive configuration
Component
CU320
Line filters
Line reactor
Active Line Module 36 kW
Motor Module 18 A
Motor Module 30 A
SMC
SITOP 20
Line Contactor
Total:
Assumption:
Free-standing cabinet surface area A = 5 m
Temperature difference between the room and cabinet interior ∆T = 10 K
q = (2415 [W] / 10 [Κ]) - 5.5 [W / (m
Booksize Power Units
Equipment Manual, (GH2), 07/2007, 6SL3097-2AC00-0BP5
Formula to calculate the power loss
Number Total power loss [W]
(including electronic losses)
1 20
1 90
1 250
1 666
2 185.4
3 311.6
5 10
1 53
1 12
]
2
2
* K)] * 5 [m ] = 214 [W/K]
2 2
Cabinet Design and EMC Booksize
* K)]
2
Total power loss [W]
20
90
250
666
370.8
934.8
50
53
12
2446.6
8.7 Cooling
479