ABB RET670 Commissioning Manual page 130

Section 10
Testing functionality by secondary injection
Expected result: start of the protection function and trip in zone 2, when trip conditions are
fulfilled.
10.4.12.3 Test of the boundary between zone 1 and zone 2, which is defined by the
parameter
The trajectory of the impedance traverses the lens characteristic in zone 2
Preliminary steady state test at 50 Hz
• Go to Main menu/Test/Function status/Impedance protection/OutOfStep(78,Ucos)/
OOSPPAM(78,Ucos):1/Outputs to check the available service values of the function block
OOSPPAM.
• Apply the following three-phase symmetrical quantities (the phase angle is related to phase
L1):
V
=
ts
EQUATION14065 V1 EN-US
V
∠
ts
EQUATION14058 V1 EN-US
frequency of V
I
50 s
EQUATION14059 V1 EN-US
∠I
50s
frequency of I
It
fs
EQUATION14062 V1 EN-US
∠I
tfs
frequency of I
• Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are according to the injected
quantities and that ROTORANG is close to 3.14 rad. For this particular injection the service
values are:
•
•
•
•
•
Note that these values identify a point inside the lens characteristic, in the Zone 2, that is close to
the boundary between zone 1 and zone 2. The START is issued, but no TRIP is performed.
124
ReachZ1
V
VT s ,
1 1 . V 1 1 1435 .
× × = ×
t RZ , 1
V
VT p
,
ForwardX
 
arctan arctan
=  =

ForwardR
 
= 50 Hz
ts
I 1
CTs
I 10459
= × = ×
50
I 9000
CTp
= 0º
= 50 Hz
50s
I 1
CTs
I 10459
= × = ×
tf
I 9000
CTp
= 0º
= 50 Hz
tfs
VOLTAGE = 1.58 kV
CURRENT = 20918 A
R = 1.08%
X = 7.85%
ROTORANG = -3.04 rad
0 1 .
11 44 . V
× =
13 8 .
59 33 .
 
82. . 14°
 =

8 19 .
 
= . 1 162 A
1 162 . A
=
1MRK 504 154-UUS B
GUID-BE180E07-7D4B-4842-81FB-244DE8897430 v1
GUID-17F6AC8D-1F57-4245-A61D-776D469DD153 v1
GUID-3D42E43D-873E-4271-9AAF-3B2789FF3B17 v1
(Equation 37)
(Equation 38)
(Equation 39)
(Equation 40)
Commissioning manual