Further Information On Unimog Hydraulic Systems; Hydraulic Output / Standard Values - Unimog U500 Mounting Manuallines

Body & implement
Table of Contents

Advertisement

Body and Implement Mounting Guidelines U500 North America

6.4 Further information on Unimog hydraulic systems

6.4.1

Hydraulic output / standard values

The installed output is generally calculated according to the fol-
lowing formula:
=
P
1714
P
= Output [hp]
Q = Flow rate [gal/min]
p
= Pressure [PSI]
Total degree of efficiency (depends on pressure, flow
η
=
rate/speed, temperature, leakage etc.)
Note:
Due to the range of the degree of efficiency, only the output is
calculated from the hydraulic standard values Q
gine speed) and p
(rated pressure) in order to estimate the
rated
required output.
The standard output is thus:
Q
*
p
P =
max
Rated
E
1714
.
29
Examples:
Power hydraulics, closed circuit:
33.02 gal/min, 4350 PSI
Power hydraulics, open circuit:
23.78 gal/min, 4060 PSI
The engine output to be applied for driving purposes is therefore
always higher than the standard value. The hydraulic output pro-
vided is always lower than the standard value.
August 2005
Q
*
p
η
*
total
.
29
(at rated en-
max
with h
= 1
total
P = 83.8 hp
P = 56.32 hp
Corresponding formula in metric units:
=
P
P
= Output [kW]
Q = Flow rate [l/min]
p
= Pressure [bar]
Total degree of efficiency (depends on pressure, flow
η
=
rate/speed, temperature, leakage etc.)
Q
*
p
P =
max
ratedn
E
600
Examples:
Power hydraulics, closed circuit:
125 l/min, 300 bar
Power hydraulics, open circuit:
90 l/min, 280 bar
Hydraulic system
Q
*
p
η
*
total
600
with h
= 1
total
P = 62.5 kW
P = 42 kW
Page 219 of
294

Advertisement

Table of Contents
loading

Table of Contents