Mohr's Circle (14, 4); Waves (15) - HP 48gII Advanced User's Reference Manual

Solution: x1=18933.9405_kPa, y1=821.0595_kPa, x1y1= -686.2151_kPa.

Mohr's Circle (14, 4)

Equations:
1 =
S I N 2 p 1
p 2 = p 1
s = p 1 45
Example:
Given:
x=-5600_psi, y=-18400_psi, xy=4800_psi.
Solution:
1= -4000_psi, 2= -20000_psi, p1=18.4349_°, p2=108.4349_°, max=8000_psi,
s= -26.5651_°, avg= -12000_psi.

Waves (15)

Variable Description
Sound level
Wavelength
Angular frequency
Density of medium
B
Bulk modulus of elasticity
f
Frequency
I
Sound intensity
k
Angular wave number
s
Longitudinal displacement at x and t
x + y x – y
2
-- - - - - - - - - - - - - - - - - - - - - + - - - - - - - - - - ---------- - + xy
2 2
1 + 2 = x + y
x y
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - --------------------- -
=
2
x – y
⎛ ⎞
2
- - - - - - - - - - - - - - - - - - - - - + xy
⎝ ⎠
2
+ 90 max = -------------------- -
– --------------------- -
avg =
1 – 2
2
x + y
2
Equation Reference 5-57