Solenoid Inductance (2, 20); Toroid Inductance (2, 21) - HP 48gII Advanced User's Reference Manual

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Example:
Given:
r=1, ro=1_cm, ri=.999_cm, L=10_cm.
Solution: C=0.0056_µF.

Solenoid Inductance (2, 20)

Equation:
L
=
Example:
Given: µr=2.5, n=40_1/cm, A= .2_cm^2, h=3_cm.
Solution: L=0.0302_mH.

Toroid Inductance (2, 21)

Equation:
µ
0
- - - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - - - L N
L
=
Example:
Given: µr=1, N=5000, h=2_cm, ri= .2_cm, ro=4_cm.
Solution: L=69.3147_mH.
2
µ
µ
0
r n
A h
2
µ
r N
h
ro
---- -
2
ri
Equation Reference 5-17

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