Shear Stress (14, 2); Stress On An Element (14, 3) - HP 48gII Advanced User's Reference Manual

Equations:
= E
Example:
Given: P=40000_lbf, L=1_ft, A=3.14159265359_in^2, E=10E6_psi,
Solution: =0.0153_in,

Shear Stress (14, 2)

Equations:
= G
Example:
Given: L=6_ft, r=2_in, J=10.4003897419_in^4, G=12000000_psi, =12000_psi.
Solution: T=5200.1949_ft lbf, =2.0626_°, =5.7296E–2_°.

Stress on an Element (14, 3)

Stresses and strains are positive in the directions shown.
Equations:
x + y
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -- - -
x 1 = +
2
x 1
x –
⎛
- - - - - - - - - - - - - - - - - - - - -
x 1 y 1 = –
⎝
2
Example:
Given: x=15000_kPa, y=4755_kPa, xy=7500_kPa, =30_°.
5-56 Equation Reference
- - -
=
L
=0.0013, =12732.3954_psi.
r
- - - - - - - - -
=
L
x – y
C O S 2 + xy SIN 2
2
+ y 1 = x + y
y
⎞
S I N 2 + x y y
⎠
P
--- -
=
A
T r
--------- -
=
J