Sphere (12, 4)
Equations:
4
3
A
=
4
V
=
-- -
r
3
Example:
Given: d=14_cm, m=3.75_kg, Id=486.5_lb in^2.
Solution: r=21.4273_cm, V=41208.7268_cm^3, A=5769.5719_cm^2, I=0.0689_kg m^2.
Solid State Devices (13)
Variable
Description
F
Forward common-base current gain
R
Reverse common-base current gain
Body factor
Modulation parameter
n
Electron mobility
p
Fermi potential
Length adjustment (PN Step Junctions), or
∆L
Channel encroachment (NMOS Transistors)
Width adjustment (PN Step Junctions), or
∆W
Width contraction (NMOS Transistors)
a
Channel thickness
Aj
Effective junction area
BV
Breakdown voltage
Cj
Junction capacitance per unit area
Cox
E1
Breakdown-voltage field factor
Emax
Maximum electric field
G0
Channel conductance
2
2
2
r
-- - m r
I
=
5
Silicon dioxide capacitance per unit area
2
Id
=
I
+
m d
Equation Reference 5-49