Calculation example
Fig. 20: Material tray level with
steel swivel
29.05.2019
Determining the permitted load-bearing capacity of the assembly workstation
a = left/b = right
Make sure that the maximum permitted load per bearing is
adhered to.
In the case of simultaneously acting forces and moments, use the
following equation to determine the load characteristic value B
B
Left-hand load characteristic value
k a
B
Right-hand load characteristic value
k b
Load characteristic value B
Material tray level with steel swivel:
n
Length L = 1250 mm (Fig. 20)
n
F
, F
zmax a
zmax b
n
M
, M
ymax a
ymax b
n
M
, M
= 0, as the concentrated load in the Y direction
y a
y b
arises in the centre, and in the X direction it arises at a dis-
tance of 0 mm.
1.
Refer to the chart (Fig. 21) for the concentrated load F
maximum deflection of L/300 (1250 mm/300) = 4.167 mm:
Fig. 21: Concentrated/distributed load dependent on length
x
Length L [mm]
y
Concentrated load [N], distributed load [N/m]
Permitted distributed load at max. deflection of L/300
Permitted concentrated load (in the centre) at max. deflec-
tion of L/300
ð F
= 295 N (F
z
Assembly workstation RK Easywork
per bearing must be £ 1!
k
Ä page 102)
= 1600 N (
= 60 Nm (
Ä page 102)
, F
= 147.5 N)
z a
z b
Assembly
:
k
at a
z
91
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