Omron CV500 Installation Manual page 12

Conformance to EC Directives
Countermeasures
Countermeasure Examples
Circuit
CR method Yes
Power
supply
Diode method No
Power
supply
Varistor method Yes
Power
supply
4. PCs complying with EC Directives also conform to the Common Emission
Standard (EN50081-2). When a PC is built into a machine, however, noise
can be generated by switching devices using relay outputs and cause the
overall machine to fail to meet the Standards. If this occurs, surge killers
must be connected or other measures taken external to the PC.
The following methods represent typical methods for reducing noise, and
may not be sufficient in all cases. Required countermeasures will vary
depending on the devices connected to the control panel, wiring, the config-
uration of the system, and other conditions.
Refer to EN50081-2 for more details.
Countermeasures are not required if the frequency of load switching for the
whole system including the PC is less than 5 times per minute.
Countermeasures are required if the frequency of load switching for the whole
system including the PC is 5 or more times per minute.
When switching an inductive load, connect a surge protector, diodes, etc., in par-
allel with the load or contact as shown below.
Current Characteristic
AC DC
Yes If the load is a relay or solenoid, there
is a time lag between the moment the
circuit is opened and the moment the
load is reset.
If the supply voltage is 24 or 48 V,
insert the surge protector in parallel
with the load. If the supply voltage is
100 to 200 V, insert the surge
protector between the contacts.
Yes The diode connected in parallel with
the load changes energy accumulated
by the coil into a current, which then
flows into the coil so that the current
will be converted into Joule heat by
the resistance of the inductive load.
This time lag, between the moment
the circuit is opened and the moment
the load is reset, caused by this
method is longer than that caused by
the CR method.
Yes The varistor method prevents the
imposition of high voltage between the
contacts by using the constant voltage
characteristic of the varistor. There is
time lag between the moment the
circuit is opened and the moment the
load is reset.
If the supply voltage is 24 or 48 V,
insert the varistor in parallel with the
load. If the supply voltage is 100 to
200 V, insert the varistor between the
contacts.
Required element
The capacitance of the capacitor must
be 1 to 0.5 µF per contact current of
1 A and resistance of the resistor must
be 0.5 to 1 Ω per contact voltage of
1 V. These values, however, vary with
the load and the characteristics of the
relay. Decide these values from
testing, and take into consideration
that the capacitance suppresses spark
discharge when the contacts are
separated and the resistance limits
the current that flows into the load
when the circuit is closed again.
The dielectric strength of the capacitor
must be 200 to 300 V. If the circuit is
an AC circuit, use a capacitor with no
polarity.
The reversed dielectric strength value
of the diode must be at least 10 times
as large as the circuit voltage value.
The forward current of the diode must
be the same as or larger than the load
current.
The reversed dielectric strength value
of the diode may be two to three times
larger than the supply voltage if the
surge protector is applied to electronic
circuits with low circuit voltages.
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