SMC Networks MSZ Series Manual page 5

Inertial Moment Formula
(1) Thin shaft
Position of rotational axis:
Perpendicular to the shaft
through one end
2
a
1
Ι
= m +m
⋅
1 2
3
(5) Thin rectangular plate
(Rectangular parallelepiped)
Position of rotational axis:
Through the center of gravity and
perpendicular to the plate (also
the same in case of a thicker
plate)
2
a
Ι
= m ⋅
12
(9) Load at lever end
Kinetic Energy/Rotation Time
Even in cases where the torque required for rotation of the load is small, damage to internal parts may result from the
inertial force of the load.
Select models giving consideration to the load's inertial moment and rotation time during operation.
(The inertial moment and rotation time charts can be used for your convenience in making model selections on Front
matter 4.)
(1) Allowable kinetic energy and rotation time adjustment range
From the table below, set the rotation time within the adjustment range for stable operation. Note that operation exceeding the
rotation time adjustment range, may lead to sticking or stopping of operation.
Size
Allowable kinetic energy (mJ)
10
20
30
50
(2) Inertial moment calculation
Since the formula for inertial moment differ depending on the configuration of the load, refer to the inertial moment calculation
formula on this page.
(Calculation of Inertial Moment Ι)
(2) Thin shaft
Position of rotational axis:
Through the shaft's center of
gravity
2
a
2
⋅
Ι
3
(6) Cylinder
(Including thin round plate)
Position of rotational axis:
Center axis
2
+ b
2
a
1 2
Ι + m a + K
= m ⋅ ⋅
2 2
1
3
(Example) When shape of m
2
2
2r
refer to (7), and K = m ⋅
2
5
7
25
48
81
Model selection
(3) Thin rectangular plate
(Rectangular parallelepiped)
Position of rotational axis:
Through the plate's center of
gravity
2
a
= m ⋅
12
(7) Solid sphere
Position of rotational axis:
Diameter
2
r
Ι
= m ⋅
2
(10) Gear transmission
is a sphere,
Number of teeth
= b
Rotation time adjustment range
for stable operation s/90
0.2 to 1.0
Series
Ι:
Inertial moment kg⋅m 2
(4) Thin rectangular plate
(Rectangular parallelepiped)
Position of rotational axis:
Perpendicular
through one of its points (also
the same in case of a thicker
plate)
2
a
Ι
= m ⋅
12
(8) Thin round plate
Position of rotational axis: Diameter
2
2r
Ι
= m ⋅
5
Number of teeth
= a
1. Find the inertial moment Ι
rotation of shaft (B).
2. Next, Ι is entered to find Ι
B
moment for the rotation of shaft (A) as
a
2
Ι Ι
= ( ) ⋅
A B
b
MSZ
m: Load mass kg
to the plate
2 2
4a + b
1
Ι
= m
⋅
1
12
2 2
4a + b
2
m
⋅
+
2
12
2
r
Ι
= m ⋅
4
for the
B
the inertial
A
Front matter 3