Siemens SIMOTICS L-1FN3 Configuration Manual page 136

Configuration
5.3 Examples
Calculating the pressure drop
Pressure drop in the secondary section cooling system
The secondary section cooling comprises a coupling point and two combi distributors.
The parallel heatsink profiles for the 1FN3300 have a length of l
sections) and l
Figure 5-17
In total, the pressure drop of the secondary section cooling system is:
Δp
S,ges
The result is:
Δp
S,ges
Δp
S,ges
Total cooling
For the total cooling, the following results:
Δp
gesamt
Δp
gesamt
Note
Pressure drop across the water lines on the customer side
For the total pressure drop, the pressure drop across water connections on the customer
side caused by the cooling medium pump - combi distributor hoses or valves must also be
considered.
134
= 0.900 m (5 secondary sections).
s 2
Example of a secondary section cooling system
= Δp ‧ l + Δp ‧ l + 2 ‧ Δp
S S 1 S S 2
= 0.09 bar/m ‧ 0.176 m +0.09 bar/m ‧ 0.900 m + 2 ‧ 0.42 bar + 0.31 bar
= 1.25 bar
= Δp + Δp + Δp
P,H P,P S,ges
= 1.90 bar
+ Δp
KV KS
= 0.32 bar + 0.33 bar + 1.25 bar
Configuration Manual, 10/2018, 6SN1197-0AB86-0BP2
= 0.716 m (4 secondary
s 1
1FN3 linear motors