Correction Of Supply Current - Eurotherm 637+/D6R KD6R Product Manual

Electrical installation
5.7

Correction of supply current

Attention in case of continous load:
Due to the capacitive input impedance of
DC-Bus, the input current is deformated.
This guides to RMS -values higher than the sinus-based calculated values. Fuses,
contactors and line filters have to be selected in respect to this effect.
In typical servo application with Stop/Go-operation (S3-Operation), the
rating to nominal data will be sufficient.
In other cases, the value has to be corrected using the following diagram.
Correction-Factor
637+/KD6R02..10.S4-7
637+/KD6R16..30.S3-7
637+/KD6R02..10.S3-3
Example:
Drive type 637+/KD6R16.S4-3 is supplied by AC 230V 3-ph.
Output data to the motor: AC 200V 16A
Output-power: Pout = 200V x 16A x 1,73 = 5,54 kW
This output-power must be generated by:
calculated supply-current Iac sinus =5,54kW / (230V x 1,73) = 13,9 A
Correction-Factor from diagram: 1,6
RMS. Supply-Current Ieff = Iac sinus x 1,6 = 22,3 A
Result :
All supply-equipment has to be selected in respect tothe enhanced current.
50
2,4
2,2
2,0
1,8
1,6
1,4
1,2
1,0
2,5
5
6,5
Iac sinus calculated
Example
Product-manual Model: 637+/D6R KD6R
1-Phase Supply 637+/ KD6R02..06.S4-3
3-Phase Supply
5
7,5 10
10 15 20
13 19,5 26
[A]
07-02-09-01-E-V0402.doc
12,5 15
25 30