GE T35 Instruction Manual page 215
Transformer protection system ur series
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5 SETTINGS
Table 5–7: PHASE AND ZERO SEQUENCE COMPENSATION FOR TYPICAL VALUES OF
w
[
]
Grounding[
comp
240° lag
270° lag
p
I
w
A
p
I
w
B
p
I
w
C
300° lag
330° lag
p
I
w
A
p
I
w
B
p
I
w
C
In our example, the following phase and zero-sequence compensation equations would be used:
For Winding 1:
2
1
p
1
-- - I
1
-- - I
1
I
=
–
–
A
A
B
3
3
For Winding 2:
1
p
2
I
w
------ - I
=
A
A
3
g) MAGNITUDE, PHASE ANGLE, AND ZERO SEQUENCE COMPENSATION
Complete magnitude, phase angle, and zero sequence compensation is as follows:
c
c
I
where:
I
w
,
w
, and
A
B
M w
= magnitude compensation factor for winding w (see previous sections)
p
c
I
I
w
,
w
, and
A
B
GE Multilin
w
] = "Not within zone"
p
I
w
I
w
=
A
C
p
I
w
I
w
=
B
A
p
I
w
I
w
=
C
B
1
1
------ - I
w
------ - I
w
=
–
C
B
3
3
1
1
------ - I
------ - I
w
w
=
–
A
C
3
3
1
1
------ - I
------ - I
w
w
=
–
B
A
3
3
p
I
w
I
w
=
–
A
B
p
I
w
I
w
=
–
B
C
p
I
w
I
w
=
–
C
A
1
1
------ - I
------ - I
w
w
=
–
A
B
3
3
1
1
------ - I
------ - I
w
w
=
–
B
C
3
3
1
1
------ - I
w
------ - I
w
=
–
C
A
3
3
1
2
1
p
-- - I
1
1
-- - I
1
-- - I
I
;
=
–
C
B
B
3
3
3
1
1
p
2
2
------ - I
I
w
------ - I
;
–
=
B
B
B
3
3
c
p
I
w
M w
I
w
, where w
=
A
A
c
p
I
w
M w
I
w
, where w
=
B
B
c
p
I
w
M w
I
w
, where w
=
C
C
c
I
w
= magnitude, phase and zero sequence compensated winding w phase currents
C
c
I
w
= phase and zero sequence compensated winding w phase currents (see earlier)
C
T35 Transformer Protection System
w
Grounding[
] = "Within zone"
2
1
p
-- - I
-- - I
I
w
w
=
–
A
C
3
3
2
1
p
-- - I
-- - I
I
w
w
=
–
B
A
3
3
2
1
p
I
w
-- - I
w
-- - I
=
–
C
B
3
3
1
p
I
w
------ - I
w
=
A
C
3
1
p
------ - I
I
w
w
=
B
A
3
1
p
------ - I
I
w
w
=
C
B
3
2
1
p
-- - I
-- - I
I
w
w
=
–
+
A
B
3
3
2
1
p
I
w
-- - I
w
-- - I
=
–
+
B
C
3
3
2
1
p
I
w
-- - I
w
-- - I
=
–
+
C
A
3
3
1
p
------ - I
I
w
w
=
A
A
3
1
p
------ - I
I
w
w
=
B
B
3
1
p
I
w
------ - I
w
=
C
C
3
1
2
p
1
-- - I
1
1
-- - I
I
;
–
=
A
C
C
C
3
3
1
1
p
2
2
------ - I
I
w
------ - I
;
–
=
C
C
C
3
3
1 2 w
=
total
1 2 w
=
total
1 2 w
=
total
5.4 SYSTEM SETUP
comp
1
-- - I
w
w
–
A
B
3
1
-- - I
w
w
–
B
C
3
1
w
-- - I
w
–
A
C
3
1
------ - I
w
–
B
3
1
------ - I
w
–
C
3
1
------ - I
w
–
A
3
1
-- - I
w
w
+
A
C
3
1
w
-- - I
w
+
A
B
3
1
w
-- - I
w
+
B
C
3
1
------ - I
w
–
B
3
1
------ - I
w
–
C
3
1
------ - I
w
–
A
3
1
1
1
-- - I
1
-- - I
1
(EQ 5.15)
–
–
A
B
3
3
1
2
------ - I
(EQ 5.16)
–
A
3
(EQ 5.17)
(EQ 5.18)
(EQ 5.19)
5-81
5
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