Checking The Floor - Nortel Passport 15000 Preparation Manual

104 Chapter 3 Site preparation
Checking the floor
241-1501-205 5.2S2
Before marking a floor with the position of the frame, ensure the proposed
position for anchoring the frame is appropriate. In a solid floor or underneath
a raised floor, verify there are no obstacles that can cause unsafe installation
of anchoring rods. For example, know where pipes, cables, or conduit pass
near the proposed anchor hole positions. For raised floors with removable
tiles, raise a tile at the proposed positions and verify that the underneath
surface is clear of obstructions. For solid floors (for example, cement or
marble inlay), review the building plans and site modification records to
determine where anything lies imbedded in the floor. For raised floors without
visual access, review the building plans and site modification records to
determine where anything lies under the floor.
For any type of floor, verify it can support a maximum weight of 726 kg
(1,600 pounds) at the position of the NEBS 2000 frame. This weight includes
a completely installed frame with two Passport 15000 or 20000 switches, full
of modules, and all power and signal cabling that fits inside the NEBS 2000
footprint. This maximum is a worst-case weight calculated by adding all of
the heaviest pieces of equipment that can possibly fit within the NEBS 2000
footprint.
Note: The worst-case weight is not likely to be reached by an average
configuration of hardware. For detailed information on calculating the
actual weight of your configuration, see "Equipment size and weight"
(page 58).
When considering the rating of your raised floor relative to the surface area
to be occupied by the frame, include
38.1 + 30.48 cm = 68.58 cm (or 15 + 12 in. = 27 in.)
of aisle area in front and behind the frame. This aisle area is half the required
minimum space in front of and behind a Passport 15000 or 20000 in a NEBS
2000 frame. With the frame and the aisle space, the total surface area of the
floor would be
(38.1 + 60 + 30.48 cm) times 60 cm = 7,714.8 sq cm = 0.77148 square m
or
(15 + 21.25 + 12 in.) times 21.25 in. = 1025.3 sq in. = 7.12 square ft