Mitsubishi MELSEC AJ65BT-R2 User Manual page 42

3 SPECIFICATIONS
(b) Reception time
An example for calculating the reception time when receiving 10 words (20
bytes) of data is shown below.
Transmission size of each area
Transmission speed
No. of connected modules
Master station sequence program scan time
Transmission speed
Data bit length
Stop bit length
Parity bit
1) When the master station is the A/QnA series
LS = 51.2 {29.4 + (8 × 4.8) + (8 × 9.6) + (1 × 32.4) + (1 × 4.8) + (1 × 9.6)}
+ 1300 = 11100 µ s (11.1ms)
Data reception time = 20 × 10/9600 = 0.0208s (20.8ms)
Reception time
2) When the master station is the Q series
LS = 51.2 {27 + (8 × 4.8) + (8 × 9.6) + (1 × 30) + (1 × 4.8) + (1 × 9.6)}
+ 1300 + 0 + 0 = 10854 µ s (10.9ms)
Data reception time = 20 × 10/9600 = 0.0208s (20.8ms)
Reception time
*1 RS (R2 internal processing time)
*2 Data transmission time
*3 Status storage area request/response scan (20
worth)
*4 Reception area request/response scan (200
worth)
Item
= 20 + 11.1 × 3 + (11.1 × 2) *
+ {(32 + 16)/16 × 11.1} *
= 96.3 + 3 × 11.1 + 33 × 11.1 = 495.9ms
= 20 + 10.9 × 2 + (10.9 × 2) *
+ {(32 + 16)/16 × 10.9} *
= 84.4 + 3 × 10.9 + 33 × 10.9 = 476.8ms
3 - 22
MELSEC-A
Setting details
Default value
156kbps
Only one R2 module
20ms (Hypothetical)
9600bps
8
1
Even
1 2
+ 20.8 *
3 + {(512 + 16)/16 × 11.1} *
1 2
+ 20.8 *
3 + {(512 + 16)/16 × 10.9} *
(32 words)
H
(512 words)
H
4
4