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Triangulation Example 2
On a course of 25.25° you site a buoy and
take a bearing of 25.93°. Your second
bearing reads 74.27°. If your bearing read-
ings were taken 45 minutes apart, and you
were travelling at 25 knots, what is your
distance traveled? What is the distance
from the object and the distance Abeam?
What is the distance Abeam in feet?
Steps/Keystrokes
1. Clear calculator:
[On/C] [On/C]
2. Enter course, then bearing 1 and 2:
25.25 [Course°]
25.93 [1st
74.27 [2nd
4. Enter time travelled from bearing 1 to
bearing 2:
45 [Min] [Time]
5. Enter speed and find distance travelled
between bearing 1 and bearing 2:
25 [Knots] [Speed]
[Dist]
6. Find distance from object:
[Dist]
7. Find distance Abeam then convert to
feet:
[Dist]
[Conv] [1]
30 – NautiCalc Plus
]
Ø
]
Ø
TIME
DOBJ
BEAM
™
CRSE
1
BRG
2
BRG
45:00
SPD
18.75
TRVL
0.2978497
0.2486118
1510.5942
Display
0.
25.25°
25.93°
74.27°
MIN SEC
25.
KNOT
N MI
N MI
N MI
FT
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