Siemens SINAMICS G130 Engineering Manual page 201

Example:
In the following example, we will calculate the rating of the Braking Module and braking resistor for a 450 kW Cabinet
Unit.
Mean braking power
The mean braking power is calculated as follows:
Mean braking power = 90 kW x 17 s / 90 s = 17.0
P = 4.5 x 17.0 kW
20
Peak power = 0.8 x 90 kW
Result:
The mean braking power is the determining factor in choosing the correct rating of Braking Module and braking
resistor, i.e., a braking unit of ≥ 76.5 kW must be provided.
The braking unit with 25 kW (P
When the response threshold is reduced, the required braking power P
Mean braking power = 90 kW x 17 s / 90 s = 17.0
P = 4.5 x 17.0 kW
20
Peak power = 1.06 x 90 kW
Result:
The peak power requirement is the determining factor in choosing the correct rating of Braking Module and braking
resistor, i.e., a braking unit of ≥ 95.4 kW must be provided.
The braking unit with 25 kW (P
= 76.5
= 72.0
= 100 kW) must be selected.
20
= 76.5
= 95.4
= 100 kW) must be selected.
20
Engineering Information
kW
kW
kW
is calculated as follows:
20
kW
kW
kW
SINAMICS Engineering Manual - May 2008
SINAMICS G150
201/396
© Siemens AG