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S i g n a l w i t h o u t undesired c o m p o n e n t
Fig. 11
T I M E M E A S U R E M E N T S
T h i s is the procedure for making time measurements bet-
w e e n t w o points on a waveform. T h e combination of the
S W E E P T I M E / D I V and the horizontal distance in divisions
between the t w o points is used in the calculation.
Procedure:
1. Apply the signal to be measured to the INPUT jack and
select the vertical M O D E s w i t c h to the channel to be
used. Adjust V O L T S / D I V and S W E E P T I M E / D I V c o n -
trols for a normal display.
Be sure that the V A R I A B L E control is set to CAL.
2. Using the y POSITION control set one of the points to
be used a s a reference to coincide with the horizontal
centerline.
Use the
POSITION control to set this point at the i n -
tersection of any vertical graduation line.
3. Measure
the horizontal
points.
Multiply this by the setting of the A S W E E P T I M E / D I V
control to obtain the time between the t w o points. If
horizontal " x 1 0 M A G " is used, multiply this further by
1 / 1 0 .
Using the formula:
T i m e = Horizontal distance (div) x ( S W E E P T I M E / D I V set-
ting) x " x 1 0 M A G " value"
( 1 / 1 0 )
1
[ E X A M P L E ]
For the example s h o w n in Fig. 12, the horizontal distance
between the t w o points is 5.4 divisions.
If the S W E E P T I M E / D I V is 0.2 m s / d i v w e calculate.
Substituting the given value:
T i m e = 5.4 (div) x 0.2 (ms) = 1.08 m s
2 0
A P P L I C A T I O N
distance between the t w o
- A d j u s t t o the vertical
" scale w i t h <*• P O S I T I O N
Horizontal d i s t a n c e
Fig. 1 2
F R E Q U E N C Y M E A S U R E M E N T S
Frequency measurements are made by measuring the per-
iod of one cycle of waveform and taking the reciprocal of
this time value as the frequency.
Procedure:
1. S e t the oscilloscope up to display one cycle of w a v e -
form (one period).
2. The frequency is the reciprocal of the period measured.
Using the formula:
Freq = — \ —
period
;
1 c y c l e = 4 0 /us (5 /zs/div. x 8 div.)
Fig. 1 3
[ E X A M P L E ]
For the example s h o w n in Fig. 1 3 , a period of 4 0 /zs is
observed and measured:
Substituting the given value:
Freq = 1 / [ 4 0 x 10"
] = 2.5 x 1 0
6
A d j u s t t o horizontal center
line w i t h * P O S I T I O N
= 2 5 kHz
4
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