Checking The Memory - GE DigitalFlow DF868 Programming Manual

Checking the Memory

Logging Data
MEM
Use the submenu to verify that the available log memory is
sufficient for the desired log. If the expected amount of logged data
will exceed the remaining memory capacity, the Model DF868
suggests that some old logs be cleared to make room for the new log.
Press the appropriate side of the
pane of the display screen, and complete the following steps:
1. To access the Log Menu, press
a. If you have activated the security feature (see Chapter 1,
Programming Site Data, page 1-57 for details), enter the
assigned password and press
[F2] MEM
2. Press = .
3. After noting the information, press
Menu screen.
MEM
The screen lists the number of remaining unused memory pages
out of the total number of 120 available pages. Also, the number of
pages expected to be used by all currently programmed logs is given.
If the number of pending pages exceeds the number of free pages,
additional memory may be made available by clearing some old logs
(see Chapter 5, Clearing Data).
If it is undesirable to delete old logs to free up additional memory, the
number of pages pending may be reduced by altering the parameters
of one or more of the currently active logs. For example, either
increasing the time increment or decreasing the total logging time
will reduce the memory requirements for a log file. Use the following
equations to calculate the number of pages used by a log:
number of records
number of pages
Consider a log that is set to run for 24 hours with a time increment of
3 minutes. From Equation 3-1, the number of records = (24 x 60)/3 =
480 records. Then, from Equation 3-2 above, the number of pages =
480/120 = 4 pages. Thus, at least four pages of memory must be
available for this log to run to completion. Notice that increasing the
time increment to 6 minutes or decreasing the length of the log to 12
hours would reduce the memory requirement to only 2 pages.
[SCREEN]
key to activate the desired
[LOG]
.
[ENT]
.
[ENT]
to return to the main Log
length of log
= -------------------------------------- -
time increment
number of records
= ----------------------------------------------- -
120
March 2008
(3-1)
(3-2)
3-7