Panasonic FP7 User Manual page 54

PLC Link
 Example of calculation
Condition
16 units connected to the link; no
station yet to be added
Where Max. station no. = 16,
1
Relays/registers are equally
allocated, and
Scan time for each PLC is set at 1
ms:
16 units connected to the link; no
station yet to be added
Where Max. station no. = 16,
2
Relays/registers are equally
allocated, and
Scan time for each PLC is set at 5
ms:
16 units connected to the link; 1
station yet to be added
Where Max. station no. = 16,
3
Relays/registers are equally
allocated, and
Scan time for each PLC is set at 5
ms:
8 units connected to the link; no
station yet to be added
Where Max. station no. = 8,
4
Relays/registers are equally
allocated, and
Scan time for each PLC is set at 5
ms:
2 units connected to the link; no
station yet to be added
Where Max. station no. = 2,
5
Relays/registers are equally
allocated, and
Scan time for each PLC is set at 5
ms:
2 units connected to the link; no
station yet to be added
Where Max. station no. = 2,
6
Where 32 relay points and 2W
registers are equally allocated,
and scan time for each PLC is set
at 1 ms:
4-12
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Calculation process
Ttx = 0.096
Each Pcm = 23 + (4 + 8) × 4 = 71 bytes
Tpc = Ttx × Pcm = 0.096 × 71 ≈ 6.82 ms
Each Ts = 1 + 6.82 = 7.82 ms
Tlt = 0.096 × (13 + 2 × 16) = 4.32 ms
Ttx = 0.096
Each Pcm = 23 + (4 + 8) × 4 = 71 bytes
Tpc = Ttx × Pcm = 0.096 × 71 ≈ 6.82 ms
Each Ts = 5 + 6.82 = 11.82 ms
Tlt = 0.096 × (13 + 2 × 16) = 4.32 ms
Ttx = 0.096
Each Ts = 5 + 6.82 = 11.82 ms
Tlt = 0.096 × (13 + 2 × 15) ≈ 4.13 ms
Tlk = 0.96 + 400 + 0.67 + 5 ≈ 407 ms
Note: Default value for the addition
waiting time: 400 ms
Ttx = 0.096
Each Pcm = 23 + (8 + +16) × 4 = 119
bytes
Tpc = Ttx × Pcm = 0.096 × 119 ≈ 11.43
ms
Each Ts = 5 +11.43 = 16.43 ms
Tlt = 0.096 × (13 + 2 × 8) ≈ 2.79 ms
Ttx = 0.096
Each Pcm = 23 + (32 + +64) × 4 = 407
bytes
Tpc = Ttx × Pcm = 0.096 × 407 ≈ 39.072
ms
Each Ts = 5 + +39.072 = 44.072 ms
Tlt = 0.096 × (13 + 2 × 2) ≈ 1.632 ms
Ttx = 0.096
Each Pcm = 23 + (1 + +1) × 4 = 31 bytes
Tpc = Ttx × Pcm = 0.096 × 31 ≈ 2.976 ms
Each Ts = 1 + +2.976 = 3.976 ms
Tlt = 0.096 × (13 + 2 × 2) ≈ 1.632 ms
Response time of 1
transmission cycle
(T)
T Max. = Ts + Tlt + Tso
7.82 × 16 + 4.32 + 1
= 130.44 ms
T Max. =Ts+Tlt+Tso
11.82×16+4.32+5
=198.44ms
T Max. = Ts + Tlt + Tso
+ Tlk
11.82 × 15 + 4.13 + 5 +
407
= 593.43 ms
T Max. = Ts + Tlt + Tso
16.438 + 2.79 + 5
= 139.23 ms
T Max. = Ts + Tlt + Tso
44.072 × 2 + 1.632 + 5
= 94.776 ms
T Max. = Ts + Tlt + Tso
3.976 × 2 + 1.632 + 1
= 10.584 ms