Texas Instruments TI-89 Titanium User Manual page 855

Use the "|" operator to restrict the solution interval
and/or other variables that occur in the equation or
inequality. When you find a solution in one interval,
you can use the inequality operators to exclude that
interval from subsequent searches.
is returned when no real solutions are found.
false
is returned if
value of satisfies the equation or inequality.
var
Since
solve()
can use "and," "or," and "not" to combine results from
with each other or with other Boolean
solve()
expressions.
Solutions might contain a unique new undefined
variable of the form @
interval 1–255. Such variables designate an arbitrary
integer.
In real mode, fractional powers having odd
denominators denote only the real branch. Otherwise,
multiple branched expressions such as fractional
powers, logarithms, and inverse trigonometric
functions denote only the principal branch.
Consequently,
corresponding to that one real or principal branch.
Note: See also
.
zeros()
equation1
solve( and
varOrGuess2 [
Returns candidate real solutions to the
simultaneous algebraic equations, where each
varOrGuess
solve for.
Optionally, you can specify an initial guess for a
variable. Each
variable
– or –
=
variable real or non-real number
For example,
852
can determine that any finite real
solve()
always returns a Boolean result, you
j with j being an integer in the
n
produces only solutions
solve()
, ,
cSolve() cZeros() nSolve()
equation2 ... varOrGuess1
[and ], {
}) ⇒
... ] Boolean expression
,
specifies a variable that you want to
must have the form:
varOrGuess
is valid and so is .
x x=3
In Radian angle mode:
solve(tan(x)=1/x,x)|x>0 and x<1
¸
solve(x=x+1,x) ¸
true
solve(x=x,x) ¸
2xì 1 1 and solve(x^2ƒ9,x) ¸
In Radian angle mode:
solve(sin(x)=0,x) ¸ x = @n1ø p
solve(x^(1/3)=ë 1,x) ¸
solve(‡(x)=ë 2,x) ¸
solve(ë ‡(x)=ë 2,x) ¸
, and
solve(y=x^2ì 2 and
,
x+2y=ë 1,{x,y}) ¸
Appendix A: Functions and Instructions
x =.860
false
true
x 1 and x ƒ ë 3
x = ë 1
false
x = 4
x=1 and y=ë 1
or x=ë 3/2 and y=1/4
...