Throughput - IBM DTTA-351010 - Deskstar 10.1 GB Hard Drive Specifications

3.3.5 Throughput

3.3.5.1 Simple Sequential Access
Operation
Sequential Read (Zone 0)
Sequential Read (Zone 7)
Figure 12. Simple Sequential Access Performance
| The above table gives the time required to read for a total of 8000x consecutive blocks (16,777,216 bytes)
| accessed by 128 read commands. Typical and Max values are given by 105% and 110% of T respectively
throughout following performance description.
Note: Assumes a host system responds instantaneously and host data transfer is faster than sustained data
rate.
T = A + B + C + 1 6 , 7 7 7 , 2 1 6 / D + 5 1 2 / E + D R Q
|
w h e r e :
T = C a l c u l a t e d T i m e ( s e c )
A = C o m m a n d P r o c e s s T i m e
B = A v e r a g e S e e k T i m e ( s e c )
C = A v e r a g e L a t e n c y ( s e c )
D = S u s t a i n e d D i s k B u f f e r T r a n s f e r R a t e ( b y t e / s e c )
E = B u f f e r H o s t T r a n s f e r R a t e ( b y t e / s e c )
D R Q = D a t a R e Q u e s t i n t e r v a l ( s e c )
3.3.5.2 Random Access
Operation
Random Read ( typical / max )
| The above table gives the time required to execute a total of 1000x read commands which access a random
LBA.
| T = ( A + B + C + 5 1 2 / D + 5 1 2 / E + D R Q ) * 4 0 9 6
w h e r e :
T = C a l c u l a t e d T i m e ( s e c )
A = C o m m a n d P r o c e s s T i m e
B = A v e r a g e S e e k T i m e ( s e c )
C = L a t e n c y ( s e c )
D = A v e r a g e S u s t a i n e d D i s k B u f f e r T r a n s f e r R a t e ( b y t e / s e c )
E = B u f f e r H o s t T r a n s f e r R a t e ( b y t e / s e c )
D R Q = D a t a R e Q u e s t i n t e r v a l ( s e c )
DTTA-35xxxx
typical / max.
1.4 sec / 1.5 sec
2.6 sec / 2.7 sec
( C o m m a n d o v e r h e a d ) ( s e c )
DTTA-35xxxx
63 sec / 66 sec
( C o m m a n d o v e r h e a d ) ( s e c )
DTTA-37xxxx
typical / max.
1.3 sec / 1.4 sec
2.2 sec / 2.3 sec
DTTA-37xxxx
58 sec / 60 sec
13
Drive Characteristics