HP 49g+ User Manual page 474

Graphing calculator
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produces the vector potential function Φ
= [0, ZYX-2YX, Y-(2ZX-X)], which is
2
different from Φ
. The last command in the screen shot shows that indeed F =
1
Φ
. Thus, a vector potential function is not uniquely determined.
2
The components of the given vector field, F(x,y,z) = f(x,y,z)i+g(x,y,z)j
+h(x,y,z)k, and those of the vector potential function, Φ(x,y,z) =
(x,y,z)i+ (x,y,z)j+ (x,y,z)k, are related by f =
/ y -
/ x, g =
/ z -
/ x, and h =
/ x -
/ y.
A condition for function Φ(x,y,z) to exists is that div F =
F = 0, i.e., f/ x +
g/ y + f/ z = 0. Thus, if this condition is not satisfied, the vector potential
function Φ(x,y,z) does not exist. For example, given F = [X+Y,X-Y,Z^2],
function VPOTENTIAL returns an error message, since function F does not
satisfy the condition
F = 0:
The condition
F
0 is verified in the following screen shot:
Page 15-7

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