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Example:
Main tube of unit
1st branch
Unit distribution tube
G
Example of each tubing length
Main tubing
Distribution joint tubing
LA = 131 ft.
Indoor side
LB = 16 ft.
1 = 16 ft.
LC = 16 ft.
2 = 16 ft.
LD = 49 ft.
3 = 7 ft.
G
Obtain charge amount for each tubing size
Note that the charge amounts per 3.3 ft. are different for each liquid tubing size.
ø3/8" (ø9.52) → LA + LB + LC + LD
ø1/4" (ø6.35) →
1 + 2 + 3 + 4 + 5 : 75 ft. × 0.279 oz/ft.
Additional refrigerant charge amount is 147 oz.
Be sure to check the limit
CAUTION
density for the room in which
the indoor unit is installed.
Checking of limit density
Density limit is determined on the basis of the size of a
room using an indoor unit of minimum capacity. For
instance, when an indoor unit is used in a room (floor area
× ceiling height 8.8 ft. = room volume 704 ft.
80 ft
2
graph at right shows that the minimum room volume
should be 497 ft.
3
(floor area 56 ft.
oz. Accordingly, openings such as louvers are required for
this room.
<Determination by calculation>
Overall refrigerant charge amount for the air conditioner: oz
(Minimum room volume for indoor unit: ft.
= 147 (oz) + 123 (oz) = 0.38 (oz/ft.
3
704 (ft.
)
Therefore, openings such as louvers are required for this
room.
L1
LA
L2
LB
LC
2
1
model 0752 model 0952 model 1252 model 1852
4 = 20 ft.
5 = 16 ft.
: 212 ft. × 0.602 oz/ft. = 127 oz
), the
3
2
) for refrigerant of 147
3
)
3
) > 0.3 (oz/ft.
3
)
LN
n
model 1852
3
n–1
= 20 oz
Total
147 oz
ft.
3
4000
Range below
3500
the density limit of
3000
3
0.3 oz/ft.
(countermeasures
2500
not needed)
2000
1500
1000
500
0
0
200
400
Total amount of refrigerant
16
ft.
2
454
398
341
284
227
170
Range above
the density limit of
114
3
0.3 oz/ft.
57
(countermeasures
needed)
0
600
800 1000 1200
oz
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