GE KVGC 202 Technical Manual page 58

KVCG202/EN M/H11
Figure 27:
2R = 2 +
L RICT2
Therefore:
(R
R = R +
L ICT2
KVGC202 burden for LDC = 0.007Ω at In
Therefore:
RLDC = 0.007Ω
And
R
L
X = <0.0526
R
LDC
Therefore:
(R
ICT2
R +
ICT1
100
or RLDC must be increased to RLDC' via a series resistor so that:

R > 19 R

LDC'
e.g.
R = 0.02
ICT1
This gives:

R > 19  0.02 +
LDC'
> 0.475
R ' = R + R
LDC LDC
Therefore:
Rs > 0.475 – 0.007
> 0.468
Choose a value of 0.5Ω.
Required continuous current capability
2In = 10A
2(R + R ')
ICT2 L
100
+ R ')
ICT2 L
100
+ R )
L'
<0.0526

(R + R )
ICT2 L'
+

ICT1
100
R = 0.3
ICT2
R ' = 0.2
L

(0.03 + 0.2)

100
S
Technical Manual
KVGC202