Xerox Printer User Manual page 73

Xerox printer user manual
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HOST FORMS DESCRIPTION LANGUAGE 3.2 FOR IBM MVS CREATING FORMS
Table 5-1. Determining interword gap
The interword
multiplier:
INTERWORD .5
no SPACING operand
INTERWORD .5
INTERWORD 1.0
no SPACING operand
INTERWORD 1.0
(no INTERWORD
no SPACING operand
command specified,
defaults to 1.0)
(no INTERWORD
command specified,
defaults to 1.0)
1
Valid for fully justifed text only
HFDL uses the interword gap you specify as the minimum value.
For fully justified text, HFDL adjusts the interword gap when
needed.
For the INTERWORD command description and syntax, refer to
the "Using HFDL commands" chapter of this manual.
The example in Figure 5-2 shows MYFORM being compiled with
SPACING specified. The EN space will be used along with the
value specified by the INTERWORD FSL command to determine
the interword gap for this form.
Figure 5-2.
COMPILE FSL=XFFSL(MYFORM) VERSion=HC SPACING
GROup=name specifies a user–assigned optional "name" to the
form. This allows you to group forms in the database for
subsequent listing, downloading, and so on. For example, list all
forms with GROUP=MEDINS. The maximum size of the field is
8 bytes.
KEYboard=name specifies the keyboard map you want to use in
the compilation of the form. name is a maximum 8-character
string. The compiler retrieves the requested keyboard map and
associated font map. Then the compiler maps the characters
entered on the form to the corresponding graphic
representations in the Xerox printer fonts. If no keyboard name
is entered, no keyboard mapping occurs. The font characters are
translated directly from EBCDIC to ASCII and then located in the
font based on their ASCII value. For more information, refer to
the Xerox Print Resources Manager/Host Forms Description
Language 3.2 for IBM MVS Managing Resources manual.
MANAGING AND PRINTING SAMPLE FORMS
applied to the base
gap, specified by:
1
COMPILE SPACING
1
COMPILE SPACING
(1.0) * the width of ASCII
COMPILE SPACING
1
SPACING compile syntax
equals an
interword gap of:
.5 * the width of ASCII
code point X'20'
.5 * the EN space
1.0 * the width of ASCII
code point X'20'
1.0 * the EN space
code point X'20'
(1.0) the EN space
5–3

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