Bryant 524J Installation, Start-Up And Service Instructions Manual page 16

UNIT V ---PH ---Hz
208/230--- 3--- 60
524J*25A
460--- 3--- 60
524J*25H
575--- 3--- 60
208/230--- 3--- 60
460--- 3--- 60
524J*28A
575--- 3--- 60
208/230--- 3--- 60
460--- 3--- 60
524J*30A
575--- 3--- 60
See Legend and Notes below.
UNIT V ---PH ---Hz*
208/230--- 3--- 60
524J*25A
460--- 3--- 60
524J*25H
575--- 3--- 60
208/230--- 3--- 60
524J*28A
460--- 3--- 60
524J*30A
575--- 3--- 60
See Legend and Notes below.
Legend and Notes for Tables 4 and 5
LEGEND:
FLA --- Full Load Amps
MOCP --- Maximum Overcurrent Protection
{ Motors are designed for satisfactory operation within 10% of
normal voltage shown. Voltages should not exceed the limits
shown in the Voltage Limits column.
NOTES:
1. Minimum circuit amps (MCA) and MOCP values are calcu-
lated in accordance with The NEC. Article 440.
2. Motor FLA values are established in accordance with Under-
writers' Laboratories (UL). Standard 1995.
3. Unbalanced 3-Phase Supply Voltage
Never operate a motor where a phase imbalance in supply
voltage is greater than 2%. Use the formula in the example
(see column to the right) to determine the percentage of volt-
age imbalance.
4. Installation with Accessory Electric Heaters
Size the Field Power Wiring between the heater TB1 and the
524J indoor fan motor per NEC Article 430--- 28 (1) or (2)
(depends on length of conduit between heater enclosure and
524J power entry location). Install wires in field --- installed
conduit.
Table 4 – Electrical Data, Standard Motors
VOLTAGE
{
LIMITS
187--- 253
414--- 506
518--- 632
187--- 253
414--- 506
518--- 632
187--- 253
414--- 506
518--- 632
Table 5 – Electrical Data, Alternate Motors
VOLTAGE
LIMITS
187--- 253
414--- 506
518--- 632
187--- 253
414--- 506
518--- 632
FAN MOTOR
Hp (kW) FLA
5.0 (3.73) 14.7/13.6
5.0 (3.73) 6.8
5.0 (3.73) 5.1
7.5 (5.59) 21.4/19.4
7.5 (5.59) 9.7
7.5 (5.59) 7.8
10.0 (7.46) 28.0/25.2
10.0 (7.46) 12.6
10.0 (7.46) 10.3
FAN MOTOR
Hp (kW) FLA
7.5 (5.59) 21.4/19.4
7.5 (5.59) 9.7
7.5 (5.59) 7.8
10.0 (7.46) 28.0/25.2
10.0 (7.46) 12.6
10.0 (7.46) 10.3
Example: Supply voltage is 230-3-60
% Voltage Imbalance = 100 x
AB = 393 v
BC = 403 v
AC = 396 v
(393 + 403 + 396)
Average Voltage =
3
= 397
Determine maximum deviation from average voltage.
(AB) 397 – 393 = 4 v
(BC) 403 – 397 = 6 v
(AC) 397 – 396 = 1 v
Maximum deviation is 4 v.
Determine percent of voltage imbalance.
% Voltage Imbalance = 100 x
= 1.5%
This amount of phase imbalance is satisfactory as it is below the
maximum allowable 2%.
IMPORTANT: If the supply voltage phase imbalance is more than
2%, contact your local electric utility company immediately.
16
POWER SUPPLY
Minimum
MOCP
Circuit Amps
18.4/17.0 30/25
8.5 15
6.4 15
26.9/24.3 45/40
12.1 20
9.8 15
35.0/31.5 60/50
15.8 25
12.9 20
POWER SUPPLY
Minimum
MOCP
Circuit Amps
26.9/24.3 45/40
12.1 20
9.8 15
35.0/31.5 60/50
15.8 25
12.9 20
max voltage deviation from average voltage
average voltage
1192
=
3
6
397