Texas Instruments TI-89 Manual Book page 447

cZeros()
MATH/Algebra/Complex menu
cZeros(expression, var)
Returns a list of candidate real and non-real
values of
does this by computing
exp8list(cSolve(expression
Otherwise,
Note: See also
Note: If
functions such as
or
imag()
¥ 
(
TI-89:
of . By default, a variable is treated as a
var
real value. If you use
treated as complex.
You should also use
variables in
values. Otherwise, you may receive
unexpected results.
cZeros({expression1, expression2 [, ... ] },
{varOrGuess1,varOrGuess2 [, ... ] })
Returns candidate positions where the
expressions are zero simultaneously. Each
varOrGuess
value you seek.
Optionally, you can specify an initial guess
for a variable. Each
form:
variable
– or –
=
variable
For example,
If all of the expressions are polynomials and
you do NOT specify any initial guesses,
cZeros()
elimination method to attempt to determine
all complex zeros.
Complex zeros can include both real and
non-real zeros, as in the example to the right.
Each row of the resulting matrix represents
an alternate zero, with the components
ordered the same as the
extract a row, index the matrix by [
430 Appendix A: Functions and Instructions
list
that make
var expression
=0, ,
var) var)
is similar to
cZeros() zeros()
cSolve() , solve() , and
is non-polynomial with
expression
, ,
abs() angle() conj()
, you should place an underscore _
2  ) at the end
TI-92 Plus:
_ , the variable is
var
_ for any other
var
that might have unreal
expression
specifies an unknown whose
must have the
varOrGuess
real or non-real number
is valid and so is
x x=3+i
uses the lexical Gröbner/Buchberger
varOrGuess
Display Digits mode in
cZeros(x^5+4x^4+5x^3ì 6xì 3,x)
=0.
cZeros()
¸
.
.
zeros() .
z is treated as real:
, ,
real()
cZeros(conj(z)ì 1ì i,z) ¸
z_ is treated as complex:
cZeros(conj(z_)ì 1ì i,z_) ¸
matrix
.
Note: The following examples use an
underscore _ (
TI-92 Plus:
will be treated as complex.
cZeros({u_ù v_ì u_ì v_,v_^2+u_},
{u_,v_}) ¸
list. To
].
row
Extract row 2:
ans(1)[2] ¸
Fix 3 :
ë.612
{ë 2.125
ë 1.114 ì 1.073ø i
ë 1.114 + 1.073ø i}
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TI-89:
2 ) so that the variables
3
1/2 ì øi 1/2 +
2
3
1/2 + øi 1/2 ì
2
0 0
3
[
øi 1/2 ì
1/2 +
2
.965
{1+i}
{1ì i}
3
øi
2
3
øi
2
3
]
øi
2