Casio ClassPad 300 User Manual page 257

Analyzing a Function Used to Draw a Graph
u To determine coordinates at a particular point on a graph
Example: To graph the function
x
= 0.5, and the
(1) Display the View Window dialog box, and then configure it with the following
parameters.
xmin = –7.7, xmax = 7.7, xscale = 1
ymin = –3.8, ymax = 3.8, yscale = 1
(2) On the Graph Editor window, input and store
tap $ to graph it.
• Make sure that only
(3) To obtain the value of
y
[ -Cal].
• This displays a dialog box for specifying the
(4) For this example, input 0.5 and then tap [OK].
• This moves the pointer to the location on the graph where
x
-coordinate and
(5) To obtain the value of
x
[ -Cal].
• This displays a dialog box for specifying the
(6) For this example, input 2.2 and then tap [OK].
• This moves the pointer to the location on the graph where
x
-coordinate and
Result Screenshots
Tip
• When there are multiple results for the above procedure, press e to calculate the next value.
Pressing d returns to the previous value.
3-8-5
y x x x
= ( + 2)(
x y
-coordinate when
y
1 is checked.
y x
for a particular -value, tap [Analysis], [G-Solve], and then
y
-coordinate at that location.
x y
for a particular -value, tap [Analysis], [G-Solve], and then
y
-coordinate at that location.
20021201
– 2) and determine the
= 2.2
y x x x
= ( + 2)( – 2) into line
x
-value.
x
= 0.5, and displays the
y
-value.
y
= 2.2, and displays the
y
-coordinate when
y
1, and then