IBM 3151 User Manual page 118

Step 1
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Step 2
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Step 3
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Reference Information (emulation)
Divide the dot pattern into 7-upper, -middle, and -lower columns .
Figure 5-7 on page 5-8 shows the divided columns.
Represent the content (dot pattern) of each column in the form of
binary bits.
Note: The top dot of each column is the least significant bit.
In this case, the results are:
ue1 B'OOOOOO' mel B'110000' le1
B'OOOO'
ue2 = B'OOOOOO' me2 = B'll1000' le2 = B'OOOl'
ue3 B'OOOOOO' me3 B'111000' Ic3 B'OOOl'
ue4 B'111110' me4
=
B'111111' le4
= B'OOOO'
ue5
=
B'001100' me5 B'OOOOOO' le5 B'OOOO'
ue6 B'110000' me6 = B'OOOOOO' le6 = B'OOOO'
ue? = B'OOOOOO' me? B'OOOOll' Ie? B'OOOO'
Convert the binary form into the hexadecimal form; then add an
offset value of X'3F'.
Note: The offset value is necessary to assign the hexadecimal code
to the ORCS character that can be began from X'3F'.
In this case, the results are:
ue1
=
X'3F' mel X'6F' le1 X'3F'
ue2 = X'3F' me2 = X'??' le2 = X'40'
ue3 = X' 3F' me3 X'??'
le3
= X'40'
ue4 =
X'?D'
me4 =
X'?E'
le4 = X'3F'
ue5 = X'4B' me5 = X'3F' le5 = X'3F'
ue6 = X'6F' me6 = X'3F' le6 X'3F'
ue?
= X'3F' me? = X'42'
Ie? =
X'3F'
Chapter 5. Reference Information
5-9