Installation - New Buck Corporation COMBO COAL & WOOD STOVE Owner's Manual

MINIMUM CLEARANCES TO FLOOR AND COMBUSTIBLES
See minimum floor protector measurements ,and also for minimum clearances to combustibles, See Pages, and
Figures below
A-1. Rear Exit into Flue 6" Single Wall Pipe( Page 11)
A-2. Rear Exit into Flue 6" DVL ( Page 12)
B-1. Rear Exit to Vertical to Horizontal into Flue 6" Single Wall Pipe( Page 14)
B-2. Rear Exit to Vertical to Horizontal into Flue 6" DVL Pipe( Page 15)
C. Rear Exit to Fire Place 6" Single Wall Pipe( Page 17)
D. Rear Exit to Vertical Ceiling 6" Single Wall Pipe or 6" DVL Pipe ( Page 19)
E. Rear Exit Thru Wall, Exterior Chimney outside Residence (6" Single Wall Pipe or 6" DVL Pipe to (Listed
2100ºUL 103 HT TYPE Chimney T-Box Asembly and Listed 2100ºUL 103 HT TYPE Chimney) ( Page 21)
Floor Protection:
When installing freestanding heater ,a floor protector must be used. Must have minimum R-value of 1.8.
How to use alternate materials and how to calculate equivalent thickness.
An easy means of determining if a proposed alternate floor protector meets requirements listed in the appliance
manual is to follow this procedure:
1. Convert specification to R-value:
R-value is given—no conversion is needed.
K– factor is given with a required thickness (T) in inches:
C-factor is given: R=1/C
2. Determine the R-value of the proposed alternate floor protector.
Use the formula in step (1) to convert values not expressed as "R"
For multiple layers, add R-values of each layer to determine the overall R-value.
If the overall R-value of the system is greater than the R-value of the specified floor protector, the alternate is acceptable.
Example:
The specified floor protector should be 3/4" thick material with a K-factor of 0.84.
The proposed alternate is 4" brick with a C-factor of 1.25 over 1/8" mineral board with a K-factor of 0.29.
Step (a): Use formula above to convert specification to R-value. R= 1/K x T = 1/0.84 x .75 = 0.893
Step (b): Calculate R of proposed system. 4" brick of C=1.25, therefore Rbrick = 1/C = 1/1.25
=0.80 1/8" mineral board of K = 0.29, therefore Rmin.bd. =1/029 x0.125 = 0.431
Step (c): Compare proposed system R of 1.231 to specified R of 0.893. Since proposed
system R is greater than required , the system is acceptable.
Definitions:
Thermal conductance = C =
Thermal conductance = K = (Btu)(inch) =
Thermal conductance = R = (ft²)(hr)(°F) = (m²)(°K)

INSTALLATION

Btu = W
(hr)(ft²)(°F) (m²)(°K)
W
(hr)(ft²)(°f) (m)(°K)
Btu W
Page 4
= (Btu)
(hr)(tf)(°F)