Texas Instruments TI-89 Titanium Short User Manual page 283

|
@ Í
("with")
expression Boolean expression1
|
expression2
The "with" (|) symbol serves as a binary operator.
The operand to the left of | is an expression. The
operand to the right of | specifies one or more
relations that are intended to affect the
simplification of the expression. Multiple relations
after | must be joined by a logical "and".
The "with" operator provides three basic types of
functionality: substitutions, interval constraints,
and exclusions.
Substitutions are in the form of an equality, such
as
x=3
side should be a simple variable.
variable
occurrence of
Interval constraints take the form of one or more
inequalities joined by logical "and" operators.
Interval constraints also permit simplification that
otherwise might be invalid or not computable.
Exclusions use the "not equals" (/= or ƒ)
relational operator to exclude a specific value
from consideration. They are used primarily to
exclude an exact solution when using
cZeros()
!
§
(store)
expression var
!
list var
!
matrix var
!
expression fun_name(parameter1,...)
!
list ! fun_name(parameter1,...)
matrix fun_name(parameter1,...)
!
If variable
initializes it to
If already exists and if it is not locked or
var
protected, replaces its contents with
, or
list
Hint: If you plan to do symbolic computations
using undefined variables, avoid storing anything
into commonly used, one-letter variables such as
a, b, c, x, y, z, etc.
Appendix A: Functions and Instructions
H
2 Í key
key
[ and Boolean
... and Boolean expressionN
] [
or . To be most effective, the left
y=sin(x)
= will substitute
value value
in
variable expression
, , ,
fMax() fMin() solve()
key
does not exist, creates
var
, , or
expression list
.
matrix
x+1| x=3 ¸
]
x+y| x=sin(y) ¸
x+y| sin(y)=x ¸
x^3ì 2x+7! f(x) ¸
f(x)| x=‡(3) ¸
|
expression
for every
(sin(x))^2+2sin(x)ì 6| sin(x)=d
.
¸
solve(x^2ì 1=0,x)|x>0 and x<2
¸
‡(x)ù ‡(1/x)|x>0 ¸
‡(x)ù ‡(1/x) ¸
solve(x^2ì 1=0,x)| xƒ1 ¸x = ë 1
,
cSolve()
, , etc.
zeros()
p/4! myvar ¸
2cos(x)! Y1(x) ¸
{1,2,3,4}! Lst5 ¸
and
var
[1,2,3;4,5,6]! MatG ¸
.
matrix
"Hello"! str1 ¸
,
expression
4
sin(y) + y
x + y
Done
‡3 + 7
dñ +2dì 6
x = 1
1
1
x ø x
p
4
Done
{1 2 3 4}
1 2 3
[ ]
4 5 6
"Hello"
277