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Refrigerant piping installation
N The amount of Refrigerant
The calculation of the additional charge should take into account the length of pipe.
A
Product Charge(kg)
B
Additional charge (kg)
=
Total liquid pipe (m): Ø22.2mm
+
Total liquid pipe (m): Ø19.05mm
+
Total liquid pipe (m): Ø15.88mm
+
Total liquid pipe (m): Ø12.7mm
+
Total liquid pipe (m): Ø9.52mm
+
Total liquid pipe (m): Ø6.35mm
CF(kg)
+
(Correction Factor)
Total amount(kg)
CAUTION
If a negative result is obtained from
the calculation, no refrigerant needs
to be added.
N Special condition
In case of the No. of CST TQ/RAC SE/ARTCOOL SF models are over than 50% of the connected
indoor units when the total No. of connected indoor units are over than 50% of the max. connectable
indoor units.
Total amount(kg)
I Additional refrigerant charging amount (kg) :
= (A x
+ B x ß) - (AVG x ß)
• A = Total No. of TQ,SE and SF Indoor units,
• B = Total No. of except TQ,SE and SF Indoor units,
• AVG = 50% of Max. No. of connectable Indoor units.
Example)
1) Installation Information
- Outdoor unit : 6HP
- Total indoor units : 6 units (TQ 3 units, SE 2 units, BH 1 unit)
2) Information from PDB
- Max. No. of connectable indoor units : 10 units
- Calculated additional refrigerant amount = 2 kg :
3) Indoor refrigerant charging amount
= (5 units x 0.5+1 unit x 0.3) - (5 units x 0.3) = 1.3 kg :
Revised the total additional charging amount =
40
Outdoor Unit
x 0.354(kg/m)
x 0.266(kg/m)
x 0.173(kg/m)
x 0.118(kg/m)
x 0.061(kg/m)
x 0.022(kg/m)
=
+
A
B
=
+
+
A
B
C
10HP
Ex
A
C
c
d
3
B
4
B
B
b
a
B
1
Additional Charge = A x 0.061 + B x 0.061 + C x 0.061
+ (a+b+c+d+e) x 0.022 + CF
= 40 x 0.061 + 20 x 0.061 + 20 x 0.061
+ (10 x 5) x 0.022 + (0) (CF)
= 5.98(kg)
= 0.5
ß = 0.3
= 2 kg +1.3 kg
= 3.3 kg
a : ø6.35, 10m
Outdoor Unit
b : ø6.35, 10m
Indoor Unit
c : ø6.35, 10m
A : ø9.52, 40m
d : ø6.35, 10m
B : ø9.52, 20m
e : ø6.35, 10m
C : ø9.52, 20m
X
e
5
B
B
2
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