Robin America RGV4100 Service Manual page 27

(5) Appliances without any indication as to power consumption
Some appliances have no indication as to power consumption; but instead the work load (output) is
indicated. In such a case, power consumption is to be worked out according to the numerical formula
mentioned below.
(Output of electrical appliance)
(Efficiency)
Efficiencies of some electrical appliances are as follows :
Single-phase motor ................................ 0.6 to 0.75
Fluorescent lamp ................................... 0.7 to 0.8
Example 1: A 40W fluorescent lamp means that its luminous output is 40W. Its efficiency is 0.7 and
accordingly, power consumption will be 40 ÷ 0.7= 57W. As explained in Item (2), multiply
this power consumption value of 57 W by 1.2 to 2 and you will get the figure of the neces-
sary capacity of a generator. In other words, a generator with a rated output of 1000W
capacity can light nine to fourteen 40 W fluorescent lamps.
Example 2 : Generally speaking, a 400 W motor means that its work load is 400 W. Efficiency of this
motor is 0.7 and power consumption will be 400÷0.7= 570 W. When this motor is used for
a motor-driven tool, the capacity of the generator should be multiple of 570 W by 1.2 to 3 as
explained in the ltem (3). 570 (W) x 1.2 to 3 = 684 (W) to 1710 (W)
M O D E L
F e r q u e n y c
n I c a n d e s e t n a l m , p
h e a e t , r t e . c
F u l o e r c s e t n a l m , p M o o t
r d v i e n o t o , l g e n r e l a p - o
M e c r u y r a l m , p t e . c
P u m , p c o m p e r s s o , r t e
= (Power consumpition)
R G V 2 8
2 3 0 0
- r a p p o r
p r o s e 1 2 0 0
a p p o r
8 0 0 W
a p p o r
. c
5 5 0 W
The smaller the motor, the
(
lower the efficiency.
0 0 R G V
6 0
W 3 6 0
. x a p p
W 1 8 0
. x a p p
1 4 0
. x a p p
8 5 0
Table. 7-1
- 24 -
)
4 1 0 0 R G
H
0 W 4 8
o r . x a p
0 W 2 4
o r . x a p
0 W 1 6
o r . x a p
W 1 1
V 6 1 0 0
0 0 W
p o r . x
0 0 W
p o r . x
0 0 W
p o r . x
0 0 W