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5. PULSE INPUT AND COUNTING METHOD
5. PULSE INPUT AND COUNTING METHOD
Pulse Input Mode
1-phase, multiplied
by one
Down counting
1-phase, multiplied
by two
Down counting
2-phase, multiplied
by one
Down counting
2-phase, multiplied
by two
Down counting
2-phase, multiplied
by four
Down counting
This chapter describes the pulse input and counting modes of the high-speed counter
module.
(1) The pulse input mode is classified into 1-phase pulse input and 2-phase pulse
input. 1-phase pulse input is subdivided into multiplication by one and
multiplication by two, whereas 2-phase pulse input covers multiplication by one,
two and four.
The following table indicates the pulse input modes and count timing.
A
B
Up counting
RY(n+1)3
(RY(n+1)A)
A
B
RY(n+1)3
(RY(n+1)A)
A
B
Up counting
RY(n+1)3
(RY(n+1)A)
A
B
RY(n+1)3
(RY(n+1)A)
A
Up counting
B
A
B
A
Up counting
B
A
B
A
Up counting
B
A
B
(2) Even if the pulse input mode is changed, counting will start from the value at the
time the mode is changed.
Count Timing
Counts a pulse on leading edge of phase
Phase
Counts a pulse on trailing edge of phase
Phase
Counts a pulse on leading and trailing edges
of phase
Phase
Counts a pulse on leading and trailing edges
of phase
Phase
Counts a pulse on leading edge of phase
Count increases in response to phase differ-
ence between phases
Counts a pulse on trailing edge of phase
Count decreases in response to phase differ-
ence between phases
Counts a pulse on leading and trailing edges
of phase
Count increases in response to phase differ-
ence between phases
Counts a pulse on leading and trailing edges
of phase
Count decreases in response to phase differ-
ence between phases
Counts a pulse on leading and trailing edges
of phases
Count increases in response to phase differ-
ence between phases
Counts a pulse on leading and trailing edges
of phases
Count decreases in response to phase differ-
ence between phases
5 - 1
MELSEC-A
B and RY(n+1)3 (RY(n+1)A) are off.
B or RY(n+1)3 (RY(n+1)A) is on.
A.
B and RY(n+1)3 (RY(n+1)A) are off.
A.
B or RY(n+1)3 (RY(n+1)A) is on.
A and
B.
A and
B.
A.
A and
B.
A.
A and
B.
A and
B.
A and B.
A and
B.
A and
B.
A.
A.
A.
A.
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