Expr Math/String Menu - Texas Instruments TITANIUM TI-89 User Manual

expand(
expanded with respect to
var are collected. The terms and their factors are
sorted with
be some incidental factoring or expansion of the
collected coefficients. Compared to omitting
this often saves time, memory, and screen space,
while making the expression more
comprehensible.
Even when there is only one variable, using
might make the denominator factorization used
for partial fraction expansion more complete.
Hint: For rational expressions,
faster but less extreme alternative to
Note: See also
numerator over an expanded denominator.
expand(
logarithms and fractional powers regardless of
. For increased distribution of logarithms and
var
fractional powers, inequality constraints might be
necessary to guarantee that some factors are
nonnegative.
expand(
absolute values,
regardless of
Note: See also
angle-sum and multiple-angle expansion.
expr()
MATH/String menu
) ⇒ ⇒ ⇒ ⇒
string
expr(
Returns the character string contained in
an expression and immediately executes it.
818
returns
expression1,var expression
)
. Similar powers of
var
var as the main variable. There might
propFrac()
for an expanded
comDenom()
also distributes
expression1, var
[ ] )
also distributes
expression1, [ var ]
)
, and exponentials,
sign()
.
var
for trigonometric
tExpand()
expression
expand((x+y+1)^2,y) ¸
expand((x+y+1)^2,x) ¸
,
var
expand((x^2ì x+y^2ì y)/(x^2ù y^2ì x^2ù
yì xù y^2+xù y),y) ¸
expand(ans(1),x) ¸
expand((x^3+x^2ì 2)/(x^2ì 2)) ¸
var
is a
. expand(ans(1),x) ¸
expand()
ln(2xù y)+‡(2xù y) ¸
expand(ans(1)) ¸
expand(ans(1))|y>=0 ¸
ln(x) + ‡2ø ‡xø ‡y + ln(y) + ln(2)
sign(xù y)+abs(xù y)+
expand(ans(1)) ¸
sign(x)øsign(y) + |x|ø|y|+ (
expr("1+2+x^2+x") ¸
as expr("expand((1+x)^2)") ¸
string
"Define cube(x)=x^3"! funcstr ¸
expr(funcstr) ¸
cube(2) ¸
Appendix A: Functions and Instructions
yñ + 2ø yø (x + 1) + (x + 1)ñ
xñ + 2ø xø (y + 1) + (y + 1)ñ
2ø x
xñ ì 2
1 1
+
xì ‡2 x+‡2
ln(2ø xø y) + ‡(2ø xø y)
ln(xø y) + ‡2ø ‡(xø y) + ln(2)
^(2x+y) ¸
e
2ø x+y + sign(xø y) + |xø y|
e
x )
2
e
ø
xñ + x + 3
xñ + 2ø x + 1
"Define cube(x)=x^3"
+ x+1
+ x+1
y
e
Done
8