Clearances; Floor Protection - Vermont Castings Savannah SSI30 Owner's Manual

SSI30 Wood Insert
A
F
Sidewall
Clearance to Combustibles
A. To side wall
B. To mantel (12" max.)
C. To top trim (3/4" max.)
D. To side trim (3/4" max.)

Floor protection

E. In front of insert (1/2" min.)
F. To side of insert
Figure 3 -
Clearances to Combustibles
Figure 4 -
Mantel Clearance
FlOOR pROTECTION
Floor protection must be at least 3/4" minimum non-
combustible material with a "K" value of 0.84, extending
18" (457 mm) in front of and 8" (203 mm) to the side of
the fuel loading door (in the United States). In Canada, it
must extend 450 mm to the front and 200 mm to the side
of the unit.
8
Mantel
Fascia or
Trim
C
B
D
ST1065
E
Minimum
11" (279 mm)
ST1065
23" (584 mm)
SSI30 clearances
16" (406 mm)
7" (178 mm)
18" (457 mm)
8" (203 mm)
12"
Max
Offset
Adapter
ST1066
ST1066
mantel clearance
CAlCulATINg ACCEpTAblE AlTERNATE
FlOOR MATERIAlS
All floor protection must be non-combustible (i.e. metal,
brick, stone, mineral fiber, etc.). Any organic materials (i.e.
plastics, wood or paper products, etc.) are combustible and
must not be used. The floor protection specified includes
some form of thermal designation such as R-value (thermal
resistance) or k-factor (thermal conductivity).
PROCEDURE:
1. Convert specification to R-value:
•
R-value given. No conversion needed.
•
k-factor is given with a required thickness (T) in
inches: R = (1/k x T
•
k-factor is given with a required thickness (T) in
inches: R = (1/Kx12) x T
•
r-factor is given with a required thickness (T) in
inches: R = r x T
2. Determine the R-value of the proposed alternate floor
protector.
a. Use the formula in step (1) to convert values not
expressed as "R."
b. For multiple layers, add R-values of each layer to
dtetermine overal R-value.
3. If the overall R-value of the system is greater than the
R-value of the specified floor protector, the alternate
is acceptable.
EXAMplE: The specified floor protector should be 3/4"
thick material with a k-factor of 0.84. The proposed alter-
nate is 4" brick with and R-factor of 0.2 over 1/8" mineral
board with a k-factor of 0.29.
Step A. Use formula above to convert specification to R-
value. R= (1/k) x T = (1/.84) x 0.75 = 0.893
Step B. Calculate R of proposed system.
4" brick of R = 0.2, therefore: R
1/8" mineral board of k = 0.29, therefore: R
0.125 = 0.431
R = R + R
total brick mineral board
Step C. Compare proposed system R
specified R of 0.893. Since proposed system R
greater than required, the system is acceptable.
(ft 2 )(hr)(°F)
R =
Btu
(Btu)(ft)
K =
(ft 2 )(hr)(°F)

ClEARANCES

= 0.2 x 4 = 0.431
brick
mineral board
= 0.8 + 0.431 = 1.231
of 1.231 to
total
total
(Btu)(in)
k = = K x 12
(ft 2 )(hr)(°F)
(ft 2 )(hr)(°F)
1
r = =
(Btu)(in)
k
63D4004
= x
is