Viessmann VITOSOL SERIES Technical Manual page 119

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Information regarding design and operation
25
20
15
10
5
0
Temperature increase with collectors
Non-heated outdoor pool
Typical temperature curve of an outdoor pool (average monthly val-
ues)
Location:
Würzburg
Pool surface: 40 m
2
Depth:
1.5 m
Position:
sheltered and covered at night
The following diagram shows what average temperature increase can
be achieved with which ratio of absorber area to pool surface. This
ratio is independent of the collector type used due to the comparably
low collector temperatures and the operating period (summer).
Note
Heating and maintaining the pool temperature at a higher set temper-
ature using a conventional heating system does not alter this ratio.
However, the pool will be heated up much more quickly.
8
7
6
5
4
3
2
1
0
0
0.2
0.4
0.6
Ratio between the absorber area
and the pool surface area
Vitotrans 200, type WTT
Max. Vitosol connectable absorber area
VITOSOL
(cont.)
Indoor swimming pools
Indoor swimming pools generally have a higher target temperature
than open-air pools and are used throughout the year. If, over the
course of the year, a constant pool temperature is required, indoor
swimming pools must be heated in dual mode. To avoid sizing errors,
the energy demand of the pool must be measured. For this, suspend
reheating for 48 hours and determine the temperature at the beginning
and end of the test period. The daily energy demand can therefore be
calculated from the temperature differential and the capacity of the
pool. For new projects, the heat demand of the swimming pool must
be calculated.
On a summer's day (clear skies), a collector system used to heat a
swimming pool in central Europe produces energy of approx.
4.5 kWh/m
Calculation example for Vitosol 200-F
Pool surface:
Average pool depth:
Pool content:
Temperature loss over 2 days:
Daily energy demand:
Collector area:
This corresponds to 6 collectors.
For a first approximation (cost estimate), an average temperature loss
of 1 K/day can be used. With an average pool depth of 1.5 m, an energy
demand of approx. 1.74 kWh/(d·m
tain the set temperature. It is therefore sensible to use an absorber
area of approx. 0.4 m
Under the following conditions, never exceed the max. absorber area
stated in the table:
■ Design output of 600 W/m
■ Max. temperature differential between the swimming pool water
(heat exchanger flow) and the solar circuit return 10 K
0.8
1.0
1.2
Part no.
3003 453
2
28
m
2
absorber area.
2
36 m
1.5 m
3
54 m
2 K
54 m
3
· 1 K · 1.16 (kWh/K · m
62.6 kWh
62.6 kWh : 4.5 kWh/m
13.9 m
2
2
pool surface) is required to main-
2
2
per m
of pool surface.
2
3003 454
3003 455
3003 456
42
70
3
) =
2
=
12
3003 457
116
163
VIESMANN
119

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