Calculating Alternate Floor Protection - Quadra-Fire 31-I ACC Installation Manual

3100-i acc wood insert automatic combustion control (acc)
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Zero Clearance Floor Thermal Protection
ZERO
CLEARANCE
ONLY
Required
Thermal
Protection
1-1/2 inch (38mm)
Adj. Hearth
0 to 6-1/2 inch
(0 to 165mm)
Figure 9.1
ZERO
CLEARANCE
ONLY
Required
Thermal
Protection
1 inch
(25mm)
6-1/2 inch
)
(165mm
Figure 9.2
April 9, 2014
1 inch (25mm)
Support
1-1/2 inch (38mm)
1 inch (25mm)
Adj. Hearth
Support
1-1/2 inch (38mm)
C. Calculating Alternate Floor Protection
Material
Thermal Conductivity: k value
The k value indicates the amount of heat (in BTU's) that will flow
in 1 hour through 1 square foot of a uniform material 1 inch thick
for each degree (F) of temperature difference from one side of
the material to the other.
The LOWER the k factor means less heat is being conducted
through the non-combustible material to the combustible mate-
rial beneath it.
The k value of a material must be equal or smaller then the re-
quired k value to be acceptable.
(BTU) (inch)
(foot
Thermal Resistance: R value
The R value is a measure of a material's resisteance to heat
transfer.
R value is convenient when more than one material is used
since you can add the R values together, whereas you can
not do this for k value.
The HIGHER the R factor means less heat is being conduct-
ed through the non-combustible material to the combustible
material beneath it.
The R value of a material must be equal or larger then the
required R value to be acceptable.
Converting k to R:
Divide 1 by k and multiply the results times the thickness in inch-
es of the material.
R = 1/k x inches of thickness
Converting R to k:
Divide the inches of thickness by R.
k = inches of thickness/R
Calculatons:
Example: Floor protection requires k value of 0.84 and 3/4 inch
thick.
Alternative material has a k value of 0.6 and is 3/4 inch thick.
Divide 0.6 by .75 = k value of 0.80. This k value is smaller than
0.84 and therefore is acceptable.
7044-225B
(hour) (
o
F)
2
31-I ACC
9

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