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Wiring work
Example of Installation
f Total power cable length L = 328ft(100m), Running current of each units 1[A]
X
f Total 10 indoor units were installed
X
ELCB
Or MCCB+
ELB
0ft(0m)
f Apply following equation
X
n
Coef×35.6×Lk×ik
∑
(
1000×Ak
k=1
❋ ❋ Calculation
• Installing with 1 sort wire.
0.0039inch
(2.5mm
2
-2.2[V]
220[V]
• Installing with 2 different sort wire.
0.0062inch
(4.0mm
2
-1.4[V]
220[V]
30
Big Duct_IBIM_E_33766-3.indd 30
10[A]
9[A]
Indoor unit 1
32.8ft(10m)
65.6ft(20m)
) <
10% of input voltage[V]
)
0.0039inch
(2.5mm
)
2
2
2
-2.0[V]
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
)
0.0062inch
(4.0mm
)
2
2
2
-1.2[V]
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
1[A]
Indoor unit 2
············ 0.0039inch
(2.5mm
) ············
2
2
208.8[V](Within 198V~242V)
············ 0.0039inch
(2.5mm
) ············
2
2
209.5[V](Within 198V~242V)
Indoor unit 10
328ft(100m)
it's okay
it's okay
2012-01-13 오후 9:40:33
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