Samsung AVXWN Installation Manual page 18

Specification of electronic wire
Power supply MCCB
Max : 242V
X A
Min : 198V
 Decide the capacity of ELCB(or MCCB+ELB) by below formula.
The capacity of ELCB(or MCCB+ELB) X [A] = 1.25 X 1.1 X ∑ Ai
X : The capacity of ELCB(or MCCB+ELB).
 ∑ Ai : Sum of Rating currents of each indoor unit.
Refer to each installation manual about the rating current of indoor unit.
Decide the power cable specification and maximum

length within 10% power drop among indoor units.
n
∑ (
k=1
coef: 1.55
: Distance among each indoor unit[m], A
L
k
i : Running current of each unit[A]
k
Example of Installation
- Total power cable length L = 100(m), Running current of each units 1[A]
- Total 10 indoor units were installed
ELCB
Or MCCB+
ELB
0[m]
 Apply following equation.
n Coef×35.6×L
∑ (
k=1
 Calculation
Installing with 1 sort wire.
2.5[mm ]
2
-2.2[V]
220[V]
Installing with 2 different sort wire.
4.0[mm ]
2
-1.4[V]
220[V]
AVXWN@@_IM_E_31755_5.11.10.indd 17
ELB or ELCB Power cable Earth cable
X A, 30mmA
2
2.5mm 2.5mm
0.1 sec
Coef×35.6×L ×i
10% of input
k k
) <
voltage[V]
1000×A
k
: Power cable specification[mm
k
10[A] 9[A]
Indoor unit1
10[m]
×i
10% of input
k k
) <
voltage[V]
1000×A
k
2.5[mm ]
2
-2.0[V]
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
4.0[mm ]
2
-1.2[V]
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
Communication
cable
2 2
0.75~1.5mm
Rating current
AVXWN 022
NHNH
2 ]
1[A]
Indoor unit2
20[m]
············ 2.5[mm ] ············
2
208.8[V](Within 198V~242V)
it's okay
············ 2.5[mm ] ············
2
209.5[V](Within 198V~242V)
it's okay
Unit Model Rating current
0.16A
0.16A
028
0.18A
036
0.27A
056
0.30A
071
0.16A
022
0.16A
028
0.18A
036
0.27A
056
0.30A
071
Indoor unit10
100[m]
17
E-
2010-5-11 16:28:10